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3 years ago

Divide! 2/5 divided by 1 4/5

Mathematics

1 answer:

Nikolay [14]3 years ago

6 0

Answer:

1/7

Step-by-step explanation:

hope this helped and have a great day!

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Solve the quadratic equation by using either a numeric or a graphic approach.

dimulka [17.4K]

Answer:

Step-by-step explanation:

x²-14x-49=0

x²-14x+49=49+49

(x-7)²=98

(x-7)²=49×2

x-7=±7√2

x=7+7√2=7(1+√2)≈7(1+1.414)≈7(2.414)≈16.898≈16.9

x=7-7√2=7(1-√2)≈7(1-1.414)≈-7×0.414≈-2.898≈2.9

4 0

2 years ago

An electrician charges $15 for a service call plus $25 per hour. The total bill for a recent job was $165.

Aleksandr-060686 [28]

Answer:

h = 6

Step-by-step explanation:

Equation:

15 + 25h = 165

Subtract 15 from both sides

25h = 150

Divide both sides by 25

h = 6

So 6 hours

Hope this helped :)

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3 0

3 years ago

Read 2 more answers

The product of 5 and x squared

Basile [38]

The product of 5 and x squared — 5(x)^2

3 0

3 years ago

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There are 7 students in cara art club . They need to share 2 rolls of clay equally . Cara wants to know how much clay she will g

Maslowich

It’s 14 bécate as you c a n d e e see deben times two is fourteen or maybe you do 2 7 times and you will get your answer

8 0

3 years ago

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The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l

sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

$A=\frac{\sqrt{3} }{4} x^2$

(c)

$A=\frac{3\sqrt{3} }{2} x^2$

(d)

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

$=\frac{\sqrt{3} }{4} b^2$

h=3x

b=x

now, we can plug values

$A=\frac{\sqrt{3} }{4} x^2$

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

$=6\times \frac{\sqrt{3} }{4} x^2$

$=\frac{3\sqrt{3} }{2} x^2$

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

$=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)$

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

3 0

3 years ago

Read 2 more answers