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iris [78.8K]
4 years ago
15

the length of a rectangle is 3 meters less than twice the width if the area is 104 square meters find the length

Mathematics
2 answers:
skad [1K]4 years ago
7 0

Answer:

l = 13 m

Step-by-step explanation:

Let's call the width of the rectangle x. Then we can form an expression for the length of the rectangle: 2x - 3

Now we need to form an equation for the area of the rectangle and solve it:

x(2x - 3) = 104

2x² - 3x = 104

2x² - 3x - 104 = 0 - now we need to factorize the equation

(2x + 13)(x - 8) = 0

Now we can say that x = 8 or x = -6.

Because we cannot have a negative length, x = 8 m.

Now we can workout the length using the expression that we formed at the beginning:

2x - 3 = l

2(8) - 3 = l

l = 16 - 3

l = 13 m

MrRa [10]4 years ago
6 0
X-width
2x-3-length

A=lxw
104=(2x-3)(x)
104=2x^2-3x
52=x^2-3/2(x)
52+9/16=x^2-3/2(x)+9/16
841/16=(x-3/4)^2
29/4=x-3/4
x=32/4 or 8

length is 2(8)-3 which is 13 and width is 8


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Solve the system: {4x-7y=30, 4x-5y=90
Lerok [7]

Answer:

x=60, y=30

Step-by-step explanation:

4x-7y=30

4x-5y=90

Subtract the equations

4x-7y=30-4x-5y=90

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Solve 2y=60

Divide both sides by 2

2y/2=60/2

Simplify;

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For 4x-7*30=30 for x

4x-7y*30=30

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Hope this helped!!!

7 0
3 years ago
52m when m=105 explain this to me please
JulsSmile [24]
52m when m= 105
52(105)
5,460

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5 0
3 years ago
Read 2 more answers
Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units. Which statements bes
valentinak56 [21]

Answer:

<h3>Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles.</h3><h3>The value of x is 8.</h3>

Step-by-step explanation:

Given that Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units

From the given Q is the middle point, which cut the diagonal PA into 2 equal halves.

By the definition of rhombus, diagonals meet at right angles.

Implies that PQ = QA

x+2 = 3x - 14

x-3x=-14-2

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2x = 16

dividing by 2 on both sides, we will get,

x =\frac{16}{2}

<h3>∴ x=8</h3><h3>Since Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles we can equate x+2 = 3x-14 to find the value of x.</h3>

The line segment \overrightarrow{PA}=\overrightarrow{PQ}+\overrightarrow{QA}

\overrightarrow{PA}=x+2+3x-14

=4x-12

=4(8)-12 ( since x=8)

=32-12

=20

<h3>∴ \overrightarrow{PA}=20 units</h3>
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