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4 years ago

15

How do you rearrange the equation (2x) /(4pi) +((1-x) /2) =0 to solve for x?

1 answer:

USPshnik [31]4 years ago

3 0

$\frac{2x}{4 \pi } + \frac{1-x}{2} =0 \\ 
 \frac{x}{2 \pi } + \frac{1-x}{2} = 0$
Then we will multiply both sides of the equation by 2 π :
x + π ( 1 - x ) = 0
x + π - π x = 0
x ( 1 - π ) = - π / · ( - 1 )
x ( π - 1 ) = π
x = π / ( π - 1 )

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x and y are both differentiable functions of t.

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