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3 years ago

How can I use the golden ratio? Need this answer, stop putting false please.

Mathematics

1 answer:

natulia [17]3 years ago

7 0

Hey, this is photography right?

Step 1: Evaluate the scene

Exactly how you use the golden ratio depends on the scene in front of you. Composition techniques are there to help you think about the scene instead of just pointing and shooting.

Step 2: Determine whether to use the golden ratio or the golden spiral (or even the Rule of Thirds)

Next, choose between the golden spiral and the phi grid. You can’t contort a straight object to fit inside a spiral, so if your scene has great leading lines, try the phi grid.

Step 3: Imagine the overlay and shoot

Imagining a complex spiral aligned over your photo can be tricky at first. If you simplify the concept, it’s a bit easier to manage.

First, check and see which grid overlays your camera has built-in by viewing the options in settings. If your camera has a phi grid or spiral option, turn that feature on. Most will have the Rule of Thirds. Even when that isn’t the composition guide you are using, it’s helpful to enable that feature.

Step 4: Edit

Picturing the phi grid or golden ratio spiral as you shoot is one thing, but what if you want that exact 1.618 magic number? Thankfully Photoshop (and several other photo editors) have tools for that.

Hope this helped!

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3 years ago

NO LINKS!!! What is the transformation f(x)= x^3:

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Answer:

4. Horizontal shrink by a factor of ¹/₅

5. Left 5, Up 5

6. Right 5, Down 5

Step-by-step explanation:

Transformations of Graphs (functions) is the process by which a function is moved or resized to produce a variation of the original (parent) function.

Transformations

For a > 0

$f(x+a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units left}$

$f(x-a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units right}$

$f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}$

$f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}$

$y=a\:f(x) \implies f(x) \: \textsf{stretched parallel to the y-axis (vertically) by a factor of}\:a$

$y=f(ax) \implies f(x) \: \textsf{stretched parallel to the x-axis (horizontally) by a factor of} \: \dfrac{1}{a}$

$y=-f(x) \implies f(x) \: \textsf{reflected in the} \: x \textsf{-axis}$

$y=f(-x) \implies f(x) \: \textsf{reflected in the} \: y \textsf{-axis}$

Identify the transformations that take the parent function to the given function.

Question 4

$\textsf{Parent function}: \quad f(x)=x^3$

$\textsf{Given function}: \quad f(x)=(5x)^3$

Comparing the parent function with the given function, we can see that the x-value of the parent function has been multiplied by 5.

Therefore, the transformation is:

$y=f(5x) \implies f(x) \: \textsf{stretched parallel to the x-axis (horizontally) by a factor of} \: \dfrac{1}{5}$

As a > 1, the transformation visually is a compression in the x-direction, so we can also say: Horizontal shrink by a factor of ¹/₅

Question 5

$\textsf{Parent function}: \quad f(x)=x^3$

$\textsf{Given function}: \quad f(x)=(x+5)^3+5$

Comparing the parent function with the given function, we can see that there are a series of transformations:

Step 1

5 has been added to the x-value of the parent function.

$f(x+5) \implies f(x) \: \textsf{translated}\:5\:\textsf{units left}$

Step 2

5 has then been added to function.

$f(x+5)+5 \implies f(x+5) \: \textsf{translated}\:5\:\textsf{units up}$

Transformation: Left 5, Up 5

Question 6

$\textsf{Parent function}: \quad f(x)=x^3$

$\textsf{Given function}: \quad f(x)=(x-5)^3-5$

Comparing the parent function with the given function, we can see that there are a series of transformations:

Step 1

5 has been subtracted from the x-value of the parent function.

$f(x-5) \implies f(x) \: \textsf{translated}\:5\:\textsf{units right}$

Step 2

5 has then been subtracted from function.

$f(x-5)-5 \implies f(x-5) \: \textsf{translated}\:5\:\textsf{units down}$

Transformation: Right 5, Down 5

Learn more about graph transformations here:

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