An art curator records statistics about three new exhibits at her art museum. The mean age of the artifacts and the standard dev
2 answers:
Answer:
Exhibit A shows the least consistency in the age of the artifacts in the exhibit, because its mean is the lowest .
Step-by-step explanation:
We can calculate consistency using standard deviation and mean of the given data , i.e.
Coefficient of Variation
- For Exhibit A (With Mean = 42 SD = 4.9)
Coefficient of Variation
- For Exhibit B (Mean = 96 SD = 3.7)
Coefficient of Variation
- For Exhibit C (Mean = 234 SD = 6.1)
Coefficient of Variation
The data having lower coefficient of Variation is more consistent and vice - versa.
Exhibit A shows the least consistency in the age of the artifacts in the exhibit, because its mean is the lowest .
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36 units.
Perimeter = 13 x 2 + 5 x 2
= 26 + 10
= 36 units
btw the numbers that look like a j are 5s sorry abt my hand writing.
Perimeter = 13 x 2 + 5 x 2
= 26 + 10
= 36 units
btw the numbers that look like a j are 5s sorry abt my hand writing.
Answer:
P(X>17) = 0.979
Step-by-step explanation:
Probability that a camera is defective, p = 3% = 3/100 = 0.03
20 cameras were randomly selected.i.e sample size, n = 20
Probability that a camera is working, q = 1 - p = 1 - 0.03 = 0.97
Probability that more than 17 cameras are working P ( X > 17)
This is a binomial distribution P(X = r)
P(X>17) = P(X=18) + P(X=19) + P(X=20)
P(X=18) =
P(X=18) =
P(X=18) = 0.0988
P(X=19) =
P(X=19) =
P(X=19) = 0.3364
P(X=20) =
P(X=20) =
P(X=20) = 0.5438
P(X>17) = 0.0988 + 0.3364 + 0.5438
P(X>17) = 0.979
The probability that there are more than 17 working cameras should be 0.979 for the company to accept the whole batch