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2 years ago

Suppose given parallelograms EFGH ∼ IJKL, such that m∠E=70°. Find m∠J and m∠L.

Mathematics

1 answer:

jarptica [38.1K]2 years ago

8 0

if both parallelograms are similar, that means all their angles are the same, one might be larger or smaller, but the angles are all the same for both.

in a parallelogra, opposite angles are equal, and their counterpart angle, are their supplementary sibling, namely they both siblings add to 180°.

check the picture below

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In a group of 10 kittens, 5 are female. Two kittens are chosen at random. a) Create a probability model for the number of male

olya-2409 [2.1K]

Answer:

(b) Expected number of male kitten E(x) = 1

(c) Standard deviation is ± $\frac{2}{3}$ .

Step-by-step explanation:

Given that,

Number of kittens in a group are 10. Out of these 5 are female.

To find:- (a) create a probability model of male kitten chosen.

So, total number of kitten = 10

number of female kitten = 5

then, Number of male kitten = $10-5= 5$

Now total number of ways to choosing two kittens from group of 10 = $^{10} C_{2}$

= $\frac{10!}{2!\times8!}$

= $45$

for choosing (i) No male P(x=0) = P(Two female) = $\frac{^{5} C_{2}}{45}$

= $\frac{2}{9}$

(ii) 1 male P(x=1) = P(1 male and 1 female) = $\frac{^{5} C_{1}\times^{5} C_{1}}{45}$ = $\frac{25}{45}$ = $\frac{5}{9}$

(iii) 2 male P(x=2)= P(2 male) = $\frac{^{5} C_{2}}{45}$ = $\frac{2}{9}$

$x_{i}$ 0 1 2

P(X= $x_{i}$ ) $\frac{2}{9}$ $\frac{5}{9}$ $\frac{2}{9}$

(b) what is expected number of male kittens chosen ?

Expected number of male kitten E(x) = $o\times \frac{2}{9} + 1\times \frac{5}{9} + 2\times\frac{2}{9}$

= $1$

(c) what is standard deviation ?

$\sigma(x) = \sqrt{ (E(x^{2} )-(Ex)^{2})$

No,

$Ex^{2} =o\times \frac{2}{9} + 1\times \frac{5}{9} + 4\times\frac{2}{9}$

= $\frac{13}{9}$

$\sigma(x)=\sqrt{\frac{13}{9} - 1 }$ $=\sqrt{\frac{4}{9} }$

= ± $\frac{2}{3}$

6 0

3 years ago

Jennifer is planning a holiday. The hotel costs $60 per night and her flights cost $150. She has a budget of $500 for hotel and

-BARSIC- [3]

First add 150 + 60 = 210

Second divide 500 divided by 210 = 2.3

Jennifer can stay up to 2 nights.

3 0

3 years ago

Solve the equation.9x^2 + 16 = 0

REY [17]

Step 1

Given;

$9x^2+16=0$

Required: To solve the equation.

Step 2

Solve the equation

$\begin{gathered} 9x^2+16-16=0-16 \\ 9x^2=-16 \\ \frac{9x^2}{9}=\frac{-16}{9} \\ x^2=-\frac{16}{9} \\ \sqrt{x^2}=\pm\sqrt{\frac{-16}{9}} \\ x=\sqrt{-\frac{16}{9}},\:x=-\sqrt{-\frac{16}{9}} \\ x=i\frac{4}{3},\:x=-i\frac{4}{3} \end{gathered}$

Answer;

$x=\frac{4}{3}i,\text{ -}\frac{4}{3}i$

4 0

1 year ago

will give brainliest to the person with the most detailed answer. That means tell me how you got ur answer. And the person who a

-BARSIC- [3]

Answer:

See below

Step-by-step explanation:

<u>Question 7</u>

The rate of change in Health Club A is 12 as given in slope-intercept form
The rate of change in Health Club B is 21 as given by an increase of $21 per month
The rate of change in Health Club C is 15 as given by (70-40)/(3-1)=15
The rate of change in Health Club D is 20 as given by "$20 each month for x months"
Therefore, Health Club B has the greatest rate of change of $21 per month

<u>Question 8:</u>

The initial value of Health Club A is 60 as given in slope-intercept form
The initial value of Health Club B is 0 as given by $0 for 0 months
The initial value of Health Club C is 25 as given by y=mx+b --> 40=15(1)+b --> b=25
The initial value of Health Club D is 20 as given by "A customer pays a one-time fee of $20"
Therefore, Health Club A has the greatest initial value (or y-intercept) of $60

4 0

2 years ago

Explain how u got the answer

MrRissso [65]

Answer:

rectangle = 2(50) +2(70) + 2(35) = 310

square = 2(32) + 2(12) + 2(24) = 136

Add

136 + 310 = 446 cm^2

SA = 446 cm^2

hope you can give me brainliest !

Step-by-step explanation:

8 0

3 years ago