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sdas [7]
3 years ago
13

Write a polynomial that represents the volume of a rectangular prism

Mathematics
1 answer:
sleet_krkn [62]3 years ago
4 0

Answer:

Step-by-step explanation:

volume=length×width×height

V=(4x-3)(x+1)(x+2)

=(4x-3)[x²+2x+x+2]

=(4x-3)(x²+3x+2)

=4x(x²+3x+2)-3(x²+3x+2)

=4x³+12x²+8x-3x²-9x-6

=4x³+9x²-x-6

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If U = 3 inches, V = 5 inches, W = 8 inches, X = 6 inches, Y = 8 inches, and Z = 4 inches, what is the area of the object?
BlackZzzverrR [31]

Answer:

46.5 inches

Step-by-step explanation:

if you plug all the numbers in and then change them into simple shapes, like a square, rectangle, and triangle, you can just add the areas to those shapes and add them together.

4 0
3 years ago
-<br><img src="https://tex.z-dn.net/?f=%20-%20%20%5Csqrt%7B5%20%20%7D%20%20-%203%20%5Csqrt%7B5%7D%20" id="TexFormula1" title=" -
xxTIMURxx [149]

Step-by-step explanation:

-\sqrt5-3\sqrt5=-1\sqrt5-3\sqrt5=(-1-3)\sqrt5=-4\sqrt5

3 0
3 years ago
What is the product of (-a+3)(a+4)?<br><br> a^2-a+12<br> a^2-a-12<br> -a^2-a-12<br> -a^2-a+12
Damm [24]

Answer:

-a^2 + -a + 12

Step-by-step explanation:

Expand the following:

(3 - a) (a + 4)

(3 - a) (a + 4) = (3) (a) + (3) (4) + (-a) (a) + (-a) (4):

-a a + 3 a - 4 a + 3 4

3×4 = 12:

-a a + 3 a - 4 a + 12

-a a = -a^2:

-a^2 + 3 a - 4 a + 12

Grouping like terms, -a^2 + 3 a + 4 (-1) a + 12 = -a^2 + (3 a - 4 a) + 12:

-a^2 + (3 a - 4 a) + 12

3 a - 4 a = -a:

Answer: -a^2 + -a + 12

4 0
3 years ago
Read 2 more answers
​temperature rose 7° between 9 AM and 2 PM yesterday the temperature at 2 PM was 75 Fahrenheit Wally use the following question
Verdich [7]
The answer is 68 because if it rose between the times it would mean you minus 7 from 75
3 0
3 years ago
PLEASE HELP
Lera25 [3.4K]

Answer:

To construct the Square using a compass and straight edge, you have written the steps not in proper order. I am rearranging the steps for you

1. Construct horizontal ​ H J¯¯¯¯¯

2. ​Construct a circle with point H as the center and a circle with point J as a center with each circle having radius HJ .

3.Label the point of intersection of the two circles above​ ​ HJ¯¯¯¯¯ ​​, point K, and the point of intersection of the two circles below ​ HJ¯¯¯¯¯ ​, point L.

4.Construct KL¯¯¯¯¯ , the perpendicular bisector of ​ HJ¯¯¯¯¯ ​, intersecting​ ​ HJ¯¯¯¯¯ ​ ​​at point M.

5.Construct a circle with point M as the center with radius MJ .

6.Label the point of intersection of circle M and ​ KL¯¯¯¯¯ ​ closest to point K, point N, and the point of intersection of circle M and ​ KL¯¯¯¯¯ ​  closest to point L, point O.

7.Construct HN¯¯¯¯¯¯ , NJ¯¯¯¯¯ , JO¯¯¯¯¯ , and OH¯¯¯¯¯¯ to complete square HNJO .





3 0
2 years ago
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