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STALIN [3.7K]
3 years ago
8

The sum of the measures of two complementary angles exceeds the difference of their measures by 72°. Find the measure of the sma

ller angle. A. 18° B. 36° C. 54° D. 58°
Mathematics
1 answer:
Neporo4naja [7]3 years ago
8 0
First we need to define our conditions. Since the angles are complimentary, the sum of the angles must be equal to 90 degrees.

let x = first angle
y = second angle

x + y = 90

from the second condition in the problem 

x + y =72 + x -y
solving for x

x= 54

therefore the shorter side is 90 - 54 = y

y = 36 degree, the shorter side
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Can u solve both 20. and 22.<br><br> Geometry
SCORPION-xisa [38]

Hey there!!

(1) Both the angles sum up to be 180.

(2) Both the angles sum up to be 90

_________________

(1) 4x+5+8x-5=180

... 12x=180

... x= 180/12

... x = 15

________________

(2) 4z+3z+6=90

... 7z+6=90

... 7z=84

... z=84/7

... x=12

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Hope it helps!


8 0
4 years ago
-12 - 6p - (-2) simplify
FromTheMoon [43]

Answer:

-6p - 10 or -10 - 6p

Step-by-step explanation:

-12 - 6p - (-2)

= -12 - 6p + 2

= -6p - 10 or -10 - 6p

Please mark me Brainliest :)

5 0
3 years ago
Read 2 more answers
A jet plane has a takeoff speed of vto = 75 m/s and can move along the runway at an average acceleration of 1.3 m/s2. If the len
pishuonlain [190]
Initial velocity of the plane is Vo = 0.
acceleration a = 1.3 m/s2
total distance = 2.5 km = 2500m

time taken to reach 2.5 km with 1.3m/s^2 acceleration = t
S = Vo t + 0.5 a t^2
2500 = 0 + (0.5*1.3* t^2)
t^2 = 3846.15
t = 62 s

the maximum velocity plan can reach within 62 s is Vt
Vt = Vo + a t
Vt = 0 + (1.3*62)
Vt = 80.6 m/s

Since 80.6 m/s is greater than 75 m/s, plane can use this runway to takeoff with required speed.
6 0
3 years ago
Read 2 more answers
This looks pretty easy but i have no idea how you do it can someone help? <br><br> thanks :)
DochEvi [55]

Answer:

BOI YOU TALKING ABOUT SOME THIS LOOKS EASY, THIS DOESN'T EVEN LOOK EASY PLUS... i dont know the answer. Bye

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Bx-6y=18 and 2x-3y=9
Sloan [31]
X - 6y=18     
2x-3y=9    |*-2

   x -6y=18
-4x+6y=-18
----------------
-3x=0, x=0

2x-3y=9
2*0-3y=9
-3y=9, y=-9/3, y= -3
4 0
4 years ago
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