(50 PTS Trick Question)

Mathematics

2 answers:

s344n2d4d5 [400]3 years ago

6 0

(xy(2zx18+2zx yz^2))^3=
(xy(36z+2yz^3))^3=
(36xyz+2z^3y^2x)^3=
(36xyz)^3+3(36xyz)^2(2z^3y^2x)+3(36xyz)(2z^3y^2x)^2+ (2z^3y^2x)^3
=46656x^3y^3z^3+3888(2z^5y^4x^3)+108 (4z^73y^5x^3)+8z^9y^6x^3

andrey2020 [161]3 years ago

6 0

Work out all the parentheses and then raise it all to the third power.

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PLEASE HELP!

34kurt

It's both. Look at the gradients between one point then the one after it. It stays constant from one to the next. (Gradient is 2 by the way: (5-3)/(2-1))

3 0

3 years ago

Read 2 more answers

The diagonals of this rhombus are 8 and 16 units long. Their intersection creates four right angles, two 4-unit-long segments, a

Roman55 [17]

Answer:

$64\ \text{sq. units}$

Step-by-step explanation:

Area of a rhombus is the product of the length of the diagonals divided by two.

Length of one diagonal is 8 units and the other diagonal is 16 units

Area is given by

$A=\dfrac{8\times 16}{2}\\\Rightarrow A=64\ \text{sq. units}$

The area of the rhombus is $64\ \text{sq. units}$

Another approach is the diagonals have created 4 triangles where the base and is height is either 4 units long or 8 units long so the area of the rhombus would be the area of the 4 triangles.

$A=4\times \dfrac{1}{2}\times 4\times 8\\\Rightarrow A=64\ \text{sq. units}$