Answer:
The sum of relative frequencies is equal to one, since the sum of all fractional parts must equal the whole.
Answer:
The answer to your question is: 40.8 g of NaN₃
Step-by-step explanation:
NaN₃ mass = ?
nitrogen = 1.2 moles
Equation
2NaN₃ ⇒ 2Na + 3N2
2 moles of NaN₃ ----------------- 3 moles of N₂
x ------------------ 1.2 moles of N₂
x = (1.2 x 2) / 3
x = 2.4/ 3
x = 0.8 moles of NaN₃
MW NaN₃ = 23 + 28
= 51 g
51 g of NaN₃ ----------------- 1 mol
x ----------------- 0.8 mol
x = (0.8 x 51) / 1
x = 40.8 g of NaN₃
Answer:
Step-by-step explanation:
xy = k
where k is the constant of variation.
We can also express the relationship between x and y as:
y =
where k is the constant of variation.
Since k is constant, we can find k given any point by multiplying the x-coordinate by the y-coordinate. For example, if y varies inversely as x, and x = 5 when y = 2, then the constant of variation is k = xy = 5(2) = 10. Thus, the equation describing this inverse variation is xy = 10 or y = .
Example 1: If y varies inversely as x, and y = 6 when x = , write an equation describing this inverse variation.
k = (6) = 8
xy = 8 or y =
Example 2: If y varies inversely as x, and the constant of variation is k = , what is y when x = 10?
xy =
10y =
y = × = × =
k is constant. Thus, given any two points (x1, y1) and (x2, y2) which satisfy the inverse variation, x1y1 = k and x2y2 = k. Consequently, x1y1 = x2y2 for any two points that satisfy the inverse variation.
Example 3: If y varies inversely as x, and y = 10 when x = 6, then what is y when x = 15?
x1y1 = x2y2
6(10) = 15y
60 = 15y
y = 4
Thus, when x = 6, y = 4.
2nd answer choice
constant of variation is xy. XY=23. If X=7 then Y=23/7.
Answer:
,..............,...............?..?.?.?.?.................
Step-by-step explanation:
Answer:
Total number of ways will be 209
Step-by-step explanation:
There are 6 boys and 4 girls in a group and 4 children are to be selected.
We have to find the number of ways that 4 children can be selected if at least one boy must be in the group of 4.
So the groups can be arranged as
(1 Boy + 3 girls), (2 Boy + 2 girls), (3 Boys + 1 girl), (4 boys)
Now we will find the combinations in which these arrangements can be done.
1 Boy and 3 girls = 
=24
2 Boy and 2 girls=
3 Boys and 1 girl = 
4 Boys = 
Now total number of ways = 24 + 90 + 80 + 15 = 209
