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crimeas [40]
3 years ago
15

I'm lost please help​

Mathematics
1 answer:
V125BC [204]3 years ago
8 0

Answer:

okay weel first you have to

Step-by-step explanation:

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Please help<br> Find the area in square units of ABC△ plotted below.
neonofarm [45]

Answer:

Use the distance formula on both points AC and AB.

<em>Distance formula is this</em><em>:</em>

<em>\begin{gathered}d=\sqrt{(x2-x1)^2+(y2-y1)^2} \\\\d=\sqrt{(1--5)^2+(8--7)^2} \\\\d=\sqrt{(6)^2+(15)^2} \\\\d=\sqrt{36+225} \\\\d=\sqrt{261} \\\\\end{gathered}d=(x2−x1)2+(y2−y1)2d=(1−−5)2+(8−−7)2d=(6)2+(15)2d=36+225d=261</em>

Distance for AC  is  16.16

Now do the same with the numbers for AB and get the distance of 5.39

2. To get the area, use the formula 1/2 x base x height

AB is the base and AC is the height.

1/2 x 16.16 x 5.39 = 43.55

the answer is 43.5

6 0
2 years ago
Help plz im sorry if im asking to many questions
Zinaida [17]

Answer:

The 3rd one 50 - 12p = 26

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
PLEASE PLEASE PLEASE HELP 2 COLUMN PROOF
Vika [28.1K]

Answer:

1. Statement: <2 and <5 are supplementary. Reason: Given

2. Reason: Vertical

3. Reason: Consecutive interior angles

4. Statement L is parallel to m. Reason: transversal makes equal angles

Have a good day!

3 0
3 years ago
Describe using words in a sentence the transformations that must be applied to the graph of f to obtain thegraph of g(x) = -2 f(
grin007 [14]

we have

f(x)

and

g(x)=-2f(x)+5

so

step 1

First transformation

Reflection about the x-axis

so

f(x) -----> -f(x)

step 2

Second transformation

A vertical dilation with a scale factor of 2

so

-f(x) ------> -2f(x)

step 3

Third transformation

A translation of 5 units up

so

-2f(x) -------> -2f(x)+5

5 0
1 year ago
Match the following items by evaluating the expression for x = -7. x-2 x-1 x0 x1 x2
frosja888 [35]

Answer:

{x}^{ - 2}  =  \frac{1}{ {x}^{2} }  \:  \: –> {7}^{ - 2}  =  \frac{1}{ {7}^{2} }  =  \frac{ 1}{49}  \\  \\  {x}^{ - 1}  =  \frac{1}{ {x}^{1} }   \: –>  {7}^{ - 1}  =  \frac{1}{ {7}^{1} } =  \frac{1}{7}  \\  \\  {x}^{0} –> {7}^{0}   = 1 \\  \\  {x}^{1}  –> {7}^{1}  = 7 \\  \\  {x}^{2}  –> {7}^{2}  = 49

7 0
2 years ago
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