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Stels [109]
3 years ago
7

Group points {(0,1),(0,5)(2,6),(3,3)}is not a function, but group points {(1,4)(2,7)(3,1)(5,7)} is a function. What do you notic

e about two groups of point? What makes it a function?
Mathematics
1 answer:
Tasya [4]3 years ago
6 0
<h2>Any value in the domain of the function should have a unique value in codomain.</h2>

Step-by-step explanation:

In the first set of points \{\text{(0,1),(0,5)(2,6),(3,3)}\},

value 0 maps to two distinct values 1,5 in the codomain.

This violates the property of functions.

The first set of points does not form a function.

In the second set of points \{\text{(1,4),(2,7)(3,1),(5,7)}\},

Every value in domain corresponds to unique value in domain.

There is no violation in the property of functions.

The second set of points does form a function.

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kotykmax [81]

Answer:

1000000

Step-by-step explanation:

4 0
3 years ago
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¿Cuál de los siguientes puntos no pertenece a la función cuadrática f(x) = 1-x^2 ?
dusya [7]

Answer:

<h2>A. (0,1)</h2>

Step-by-step explanation:

The question lacks the e=required option. Find the complete question below with options.

Which of the following points does not belong to the quadratic function

f(x) = 1-x²?

a.(0,1) b.(1,0) c.(-1,0)

Let f(x) = 0

The equation becomes 1-x² = 0

Solving 1-x² = 0 for x;

subtract 1 from both sides;

1-x²-1 = 0-1

-x² = -1

multiply both sides by minus sign

-(-x²) = -(-1)

x² = 1

take square root of both sides;

√x² = ±√1

x = ±1

x = 1 and x = -1

when x = 1

f(x) = y = 1-1²

y = 1-1

y = 0

when x = -1

f(x) = y = 1-(-1)²

y = 1-1

y = 0

Hence the coordinate of the function f(x) = 1-x² are (±1, 0) i.e (1, 0) and (-1, 0). The point that does not belong to the quadratic function is (0, 1)

3 0
3 years ago
Which of the following functions is not a sinusoid?
Nezavi [6.7K]
A sinusoid is cyclical and has a period or frequency.

y = sin x is a sinusoid, with a period of 2π.
y = √x is not a sinusoid.
y = cos x is a sinusoid with a period of 2π.

Answer: y = √x is not a sinusoid.
8 0
4 years ago
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The equation of line AB is y = 2x + 4. What is the equation of a line parallel to line AB in slope-intercept form that contains
hodyreva [135]

Answer:

Step-by-step explanation:

eq. of line parallel to AB is y=2x+a

if it passes through (3,-2) then

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