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Stels [109]
3 years ago
7

Group points {(0,1),(0,5)(2,6),(3,3)}is not a function, but group points {(1,4)(2,7)(3,1)(5,7)} is a function. What do you notic

e about two groups of point? What makes it a function?
Mathematics
1 answer:
Tasya [4]3 years ago
6 0
<h2>Any value in the domain of the function should have a unique value in codomain.</h2>

Step-by-step explanation:

In the first set of points \{\text{(0,1),(0,5)(2,6),(3,3)}\},

value 0 maps to two distinct values 1,5 in the codomain.

This violates the property of functions.

The first set of points does not form a function.

In the second set of points \{\text{(1,4),(2,7)(3,1),(5,7)}\},

Every value in domain corresponds to unique value in domain.

There is no violation in the property of functions.

The second set of points does form a function.

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Please help. I am really stuck on this little problem. I need to find the domain and Range for this graph.
Anika [276]

Answer:

This isn't the answer but if you can take a pic of this and put it in this app called "Math-way" or "Photo-math" those help me

7 0
3 years ago
A successful basketball player has a height of 6 feet 5 inches, or 196 cm. Based on statistics from a data set, his height conve
SVETLANKA909090 [29]

Answer:

The player's height is 3.02 standard deviations above the mean.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Normal distribution with parameter <em>μ</em> and <em>σ</em>.

The procedure of standardization transforms individual scores to standard scores for which we know the percentiles (if the data are normally distributed).  

Standardization does this by transforming individual scores from different normal distributions to a common normal distribution with a known mean, standard deviation, and percentiles.

A standardized score is the number of standard deviations an observation or data point is above or below the mean.

The standard score of the random variable <em>X</em> is:

Z=\frac{X-\mu}{\sigma}

These standard scores are also known as <em>z</em>-scores and they follow a Standard normal distribution, i.e. <em>N</em> (0, 1).

It is provided that the height of a successful basketball player is 196 cm.

The standard value of this height is, <em>z</em> = 3.02.

The <em>z</em>-score of 3.02 implies that the player's height is 3.02 standard deviations above the mean.

3 0
3 years ago
Calculate the following absolute values (|-1||-3|)^2
Ilya [14]

Answer:

the asnwer is ) 9

Step-by-step explanation:

1 Simplifica |-1|∣−1∣ a 11.

{(1\times |-3|)}^{2}(1×∣−3∣)

​2

​​  

2 Simplifica |-3|∣−3∣ a 33.

{(1\times 3)}^{2}(1×3)

​2

​​  

3 Simplifica 1\times 31×3 a 33.

{3}^{2}3

​2

​​  

4 Simplifica.

9

8 0
3 years ago
Please help really need to pass
VashaNatasha [74]
First add 5 to right side
\frac{x}{7} = -4+5 = 1
Next , to cancel the 7, you need to multiply by 7 on both sides
x = 1*7 = 7
8 0
4 years ago
If (x, 42) is a solution to the equation y = -6 (x – 15) – 3, find x
Molodets [167]

Put y and find x

  • y=-6(x-15)-3
  • 42=-6(x-15)
  • 42+3=-6(x-15)
  • 45=-6x+90
  • -6x=-45
  • x=45/6
  • x=15/2
8 0
2 years ago
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