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Stels [109]
3 years ago
7

Group points {(0,1),(0,5)(2,6),(3,3)}is not a function, but group points {(1,4)(2,7)(3,1)(5,7)} is a function. What do you notic

e about two groups of point? What makes it a function?
Mathematics
1 answer:
Tasya [4]3 years ago
6 0
<h2>Any value in the domain of the function should have a unique value in codomain.</h2>

Step-by-step explanation:

In the first set of points \{\text{(0,1),(0,5)(2,6),(3,3)}\},

value 0 maps to two distinct values 1,5 in the codomain.

This violates the property of functions.

The first set of points does not form a function.

In the second set of points \{\text{(1,4),(2,7)(3,1),(5,7)}\},

Every value in domain corresponds to unique value in domain.

There is no violation in the property of functions.

The second set of points does form a function.

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anyanavicka [17]

Answer:

if \:  log(x )  = 3 \\  log_{10}(x)  = 3 \\   {10}^{3}  = x \\ therfore \to \:  \boxed{x =  {10}^{3} } \\ \\  if \:  log(y )  = 2 \\  log_{10}(y)  = 2 \\   {10}^{2}  = y \\ therfore \to \:  \boxed{y=  {10}^{2} }

Step-by-step explanation:

x^2 -7xy =3000y \: then \to \\ x^2 =3000y + 7xy \\ {(10 ^{3} )}^{2}  = 3000(10)^{2}    + 7( {10}^{3} \times  {10}^{2})  \\   {10}^{6}   = 3000(10)^{2}    + 7( {10}^{3} \times  {10}^{2})  \\   {10}^{6}   = 3000(10)^{2}    + 7( {10}^{5} )   \\  {10}^{6}  = 300000 + 700000 \\   \boxed{{10}^{6}  = 1000000} \\ hence \: the \: equation \to \: x^2 -7xy =3000y \\ \boxed{ is \: corret}

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3 0
3 years ago
Help help help me THE PICTURE IS THERE UP
liubo4ka [24]

Answer: 16x -10

Step-by-step explanation:

2x + 14x = 16x

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5 0
3 years ago
Can someone please help and thank you:)
erica [24]

Answer:

8.25

Step-by-step explanation:

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3 0
2 years ago
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strojnjashka [21]

Answer:

x = -1.6

Step-by-step explanation:

To find the value of x

4x - 5 = -6x - 21

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4x + 6x = -21 + 5

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x = -16/10

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3 0
3 years ago
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If the mean of seven values is 39, find the sum of the values.
Vinvika [58]
<span>the sum of the values = 39 </span>× 7 = 273
7 0
3 years ago
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