6 boys, ratio is boy:girl 2:3
If we have
y = 6x + 1 and x - y = 11, we can take advantage of y - y = 0 as follows:
Subtract x from both sides of the 2nd equation:
-y = 11 - x
Now combine
y = 6x + 1
-y = 11 - x
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0 = 5x + 12. Solving for x, x = -12/5. Using the equation above, find y:
-y = 11 - x
= 11 - (-12/5)
= 55/5 + 12/5 = 67/5
Then the solution is (-12.5, 67/5).
Yes the ratio would change because it needs 3 times more than the original amount so you would multiply it by 3
Answer:
Tommy had 56 cents in start and Loren had 7 cents in start.
Step-by-step explanation:
Let,
x be the money Tommy have.
y be the money Loren have.
According to given statement;
Tommy had 8 times more money than Loren.
x = 8y Eqn 1
Parents gave 35 cents to Loren and Tommy spent 14 cents, therefore
x-14=y+35 Eqn 2
Putting x=8y in Eqn 2
Dividing both sides by 7
Putting y=7 in Eqn 1
Hence,
Tommy had 56 cents in start and Loren had 7 cents in start.
To find the mean just add all of them then divide the result by 8. To find the median put the numbers in order. So 3, 3, 4, 4, 13, 15, 15, 16 then find the middle number, if there is not middle number (which there isn’t) add the two middle numbers (4 and 13) to get 17 then divide 17 by 2 to get 8.5 which is the median
