Since x can be any value as long as the denominator equals 0 (it doesn't matter if it's positive or negative), we have to figure out when x^2=0, which is when x=0. Therefore, the domain is (-inf, 0) U (0, inf)
a = adult ticket price
s = student ticket price
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7a + 2s = 87
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4a + 6s = 74
4a = 74 - 6s
a = 74/4 - (6/4)s
a = 37/2 - (3/2)s
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7a + 2s = 87
7(37/2 - (3/2)s) + 2s = 87
7(37/2) - 7(3/2)s + 2s = 87
(259/2) - (21/2)s + 2s = 87
(21/2)s - 2s = (259/2) - 87
(21/2)s - (4/2)s = 259/2 - 174/2
(17/2)s = 85/2
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s = 85/2(2/17)
s = 85/17
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Answer:
s = $5
a = $11
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around 13% chance
Step-by-step explanation:
Answer:
hole at x=-3
Step-by-step explanation:
The hole is the discontinuity that exists after the fraction reduces. (Still doesn't exist for original of course)
The discontinuities for this expression is when the bottom is 0. x^2-9=0 when x=3 or x=-3 since squaring either and then subtracting 9 would lead to 0.
So anyways we have (x+3)/(x^2-9)
= (x+3)/((x-3)(x+3))
Now this equals 1/(x-3) with a hole at x=-3 since the x+3 factor was "cancelled" from the denominator.
6x+3=45
6x+3-3=45-3
6x= 42
Divide by 6 for 6x and 42
6x/6= 42/6
x= 7
Check answer by using substitution method
6x+3= 45
6(7)+3= 45
42+3= 45
45= 45
The answer is x= 7
