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3 years ago

Determine the domain of the function. f(x)=4/x^2

1 answer:

3 0

Since x can be any value as long as the denominator equals 0 (it doesn't matter if it's positive or negative), we have to figure out when x^2=0, which is when x=0. Therefore, the domain is (-inf, 0) U (0, inf)

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Solve the problem.

julsineya [31]

Answer:

2 dogs

Step-by-step explanation:

2 dogs at 1st plus 7 dogs added equals 9

3 0

3 years ago

The amount of water in a barrel decreased is 9 5/8 pints in 7 weeks

gizmo_the_mogwai [7]

Answer:

1 3/8 in one week

Step-by-step explanation:

3 0

3 years ago

Construct a 99% confidence interval to estimate the population proportion with a sample proportion equal to 0.36 and a sample s

vivado [14]

Using the z-distribution, the 99% confidence interval to estimate the population proportion is: (0.2364, 0.4836).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 99% confidence level, hence $\alpha = 0.99$ , z is the value of Z that has a p-value of $\frac{1+0.99}{2} = 0.995$ , so the critical value is z = 2.575.

The estimate and the sample size are given by:

$\pi = 0.36, n = 100$ .

Then the bounds of the interval are:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.36 - 2.575\sqrt{\frac{0.36(0.64)}{100}} = 0.2364$

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.36 + 2.575\sqrt{\frac{0.36(0.64)}{100}} = 0.4836$

The 99% confidence interval to estimate the population proportion is: (0.2364, 0.4836).

More can be learned about the z-distribution at brainly.com/question/25890103

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8 0

2 years ago

16=5a+a<br> Helppp please

Nostrana [21]

A=8/3

5a+a= 6a

16/6a= 8/3

3 0

3 years ago

Which represents a quadratic function? f(x) = −8x3 − 16x2 − 4x f (x) = x 2 + 2x − 5 f(x) = + 1 f(x) = 0x2 − 9x + 7

elena-14-01-66 [18.8K]

The answer is f(x)=x^2+2x-5
A quadratic formula must have at least one square (x^2) and cannot have higher exponents.
The reason 0x^2 doesn't count is because that will always equal zero no matter the value of x, which makes that term a constant.

4 0

3 years ago

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