Answer:
r(t) = 75 kg - (4.5 kg/wk)w
Step-by-step explanation:
Let r(t) represent the amount of rice remaining after w weeks.
Then:
r(t) = 75 kg - (4.5 kg/wk)w
please mark as brainliest
Answer:
its either 3 or 4
Step-by-step explanation:
Answer:
The desired sample size is 97.
Step-by-step explanation:
Assume that 50% people in the community that supports the political candidate.
It is provided that the candidate wants a 10% margin of error (MOE) at a 95% confidence level.
The confidence interval for the population proportion is:

Then the margin of error is:

Compute the critical value of <em>z</em> as follows:

*Use a <em>z</em>-table.
Compute the sample size as follows:

![n=[\frac{z_{\alpha/2}\times \sqrt{\hat p(1-\hat p)} }{MOE}]^{2}](https://tex.z-dn.net/?f=n%3D%5B%5Cfrac%7Bz_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csqrt%7B%5Chat%20p%281-%5Chat%20p%29%7D%20%7D%7BMOE%7D%5D%5E%7B2%7D)
![=[\frac{1.96\times \sqrt{0.50(1-0.50)} }{0.10}^{2}\\\\=[9.8]^{2}\\\\=96.04\\\\\approx 97](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1.96%5Ctimes%20%5Csqrt%7B0.50%281-0.50%29%7D%20%7D%7B0.10%7D%5E%7B2%7D%5C%5C%5C%5C%3D%5B9.8%5D%5E%7B2%7D%5C%5C%5C%5C%3D96.04%5C%5C%5C%5C%5Capprox%2097)
Thus, the desired sample size is 97.
Divide the numbers:
(4/116)/(4/4) = 1/(29)
1/29 converted into decimal = 0.0345 (rounded)
0.0345 is your answer
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80*90% = 80*0.9 so 80*0.9=72