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amid [387]
3 years ago
9

Infinite limits algebraic

Mathematics
1 answer:
Komok [63]3 years ago
7 0

Answer:

B is your answer

Step-by-step explanation:

<em><u>PLEASE MARK BRAINLIEST</u></em>

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<h2>1. 35 </h2><h2>2. 12</h2>

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Hope This helps. If it did, then....

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We must find the common denominator.

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The list of multiples of 3: 0, 3, 6, 9, 12, 15, 18, ...

The common denominator is 12.

\dfrac{3}{4}=\dfrac{3\cdot3}{4\cdot3}=\dfrac{9}{12}\\\\\dfrac{2}{3}=\dfrac{2\cdot4}{3\cdot4}=\dfrac{8}{12}

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\dfrac{3}{4}+\dfrac{2}{3}=\dfrac{9}{12}+\dfrac{8}{12}=\dfrac{9+8}{12}=\dfrac{17}{12}=\dfrac{12+5}{12}=1\dfrac{5}{12}

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