See attachments for the answers.
The general form of the quadratic equation is :

The discriminant is :

And the general solution is :
![x=\frac{-b\pm\sqrt[]{D}}{2\cdot a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7BD%7D%7D%7B2%5Ccdot%20a%7D)
So, there are 3 situations for D
1. D = 0
So, the roots of a quadratic equation are two similar roots
2. D > 0
so, roots of a quadratic equation are two different roots
3. D < 0
so, roots of a quadratic equation are not real, two comlex roots
<h2>
Answer:</h2>
(a)
(b)
(c)
<h2>
Step-by-step explanation:</h2>
We are given a function f(x) as :

(a)

We will substitute (x+h) in place of x in the function f(x) as follows:

(b)
Now on subtracting the f(x+h) obtained in part (a) with the function f(x) we have:

(c)
In this part we will divide the numerator expression which is obtained in part (b) by h to get:
Answer:
the first one is triangle and the second one is rectangle
Step-by-step explanation:
i just did it on edge