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monitta
3 years ago
11

What is the equation of the line in slope intercept form? ANSWER ASAP PLZ!!!!!!!!!!!!!

Mathematics
1 answer:
hodyreva [135]3 years ago
7 0

Equation in slope intercept form is y = 4x + 2

Step-by-step explanation:

  • Step 1: Given points are (0,2) and (1,6). Slope intercept form equation is    y = mx + b
  • Step 2: Find slope of the line using the formula m = (y2-y1)/(x2-x1)

⇒ m = (6 - 2)/(1-0) = 4/1 = 4

  • Step 3: Find the y-intercept.

⇒ b = 2

  • Step 4: Substitute values of m and b in the equation.

⇒ y = 4x + 2

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3 years ago
Find the missing term and the missing coefficient 6a −( )5a =( ) a2 − 35a
andrew11 [14]
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 Let the missing term be X
 Let the missing coefficient be Y
 Therefore, (6a – X)5a = Y(a^2) – 35a
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3 0
3 years ago
2 points) Suppose w=xy+yzw=xy+yz, where x=et, y=2+sin(t)x=et, y=2+sin⁡(t), and z=2+cos(3t)z=2+cos⁡(3t). A ) Use the chain rule t
Olenka [21]

Answer:

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Step-by-step explanation:

First, note that

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Now remember that the chain rule in several variables sates that

\frac{\partial w}{\partial t}  = \frac{\partial w}{\partial x} * \frac{\partial x}{\partial t} + \frac{\partial w}{\partial y} * \frac{\partial y}{\partial t} + \frac{\partial w}{\partial z} * \frac{\partial z}{\partial t}

Therefore the chain rule in several variables would look like this.

\frac{\partial w}{\partial t}  = y(e^t) +(x+z)*(cos(t))  - 3y*sin(3t)

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3 years ago
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