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fgiga [73]
3 years ago
6

Michael has $1,082.99 in his checking account. He is going to spend $507 43 on a new television, and he will spend the rest on

Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
3 0
He can get 12 speakers
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For bone density scores that are normally distributed with a mean of 0 and a standard deviation of​ 1, find the percentage of sc
Shkiper50 [21]

Answer:

a) Scores of 2 and higher are significantly high

b) Scores of -2 and lower are significantly low

c) Scores between -2 and 2 are not significant.

Step-by-step explanation:

Mean = 0

Standard deviation = 1

a. significantly high​ (or at least 2 standard deviations above the​ mean).

2 standard deviations above the mean is:

0 + 1*2 = 2

So scores of 2 and higher are significantly high

b. significantly low​ (or at least 2 standard deviations below the​ mean).

2 standard deviations below the mean is:

0 - 1*2 = -2

So scores of -2 and lower are significantly low

c. not significant​ (or less than 2 standard deviations away from the​ mean).

2 standard deviations above the mean is:

0 + 1*2 = 2

2 standard deviations below the mean is:

0 - 1*2 = -2

So scores between -2 and 2 are not significant.

3 0
3 years ago
Jenna’s rent is increasing from $650 per month to $700 per month the percent increase in her rent is closest to which of the fol
jok3333 [9.3K]

Answer: 7.6

Step-by-step explanation:

1) Subtract the big number by the small number

2) Divide answer by the small number

3) Multiply answer by 100

4) You get 7.692307693

Count one place to the right and get 7.6

8 0
3 years ago
Which equation describes the sum of the vectors plotted below?
Alex787 [66]

Answer: A) \   3\vec{x} -2\vec{y}  

Step-by-step explanation:

The resultant can be calculated using triangular law of vector addition as :

\rm \vec{r}=\vec{AB} +\vec{AC}=2x+y+x-3y=\boxed{3x-2y }

8 0
3 years ago
The hours a week people spend answering and sending emails is normally distributed with a standard deviation of Ï = 150 minutes.
storchak [24]

Answer:

sample size n would be 149305 large

Value of n (149305) is too high, this will be the practical problem with attempting to find this confidence interval

Step-by-step explanation:

Given that;

standard deviation α = 150 min

confidence interval = 99%

since; p( -2.576 < z < 2.576) = 0.99

so z-value for 99% CI is 2.576

E = 1 minutes

Therefore

n = [(z × α) / E ]²

so we substitute

n = [(2.576 × 150) / 1 ]²

n = [ 386.4 ]²

n = 149304.96 ≈ 149305

Therefore sample size would be 149305 large

Value of n is too high, that would be the practical problem with attempting to find this confidence interval

4 0
2 years ago
Find the Volume<br> 5 cm<br> 8 cm
padilas [110]

Answer:

it's 13 cm. its no that hard

6 0
3 years ago
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