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3 years ago

What number is 672,591 closer to

Mathematics

2 answers:

valina [46]3 years ago

6 0

That number is closer to 700,000

slavikrds [6]3 years ago

6 0

That number is closer to 700,000.

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PLZZZ HELP ASAP<br><br> Solve for x <br><br> Enter you answer in the box

Leya [2.2K]

Hey there!!

The total number of angles are 5 and the total sum of angles in a 5 sided shape is 540°

The angles given are :

107, 144, 130,x and 90

If we add them up, we get 540

Hence,

107+144+130+x+90 = 540

471 + x = 540

x = 69°

Hope my answer helps!!

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3 years ago

Simplify the expression. Write your answer as a complex number.

Amanda [17]

Answer:

Step-by-step explanation:

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3 years ago

Urgent ASAP!! Imagine math

Paraphin [41]

Answer:

Graph A = 20miles/gallon

Graph B = 20

Step-by-step explanation:

For graph A, to find the change you will need to choose two points from the graph (the easier the better)

So for example, I've chosen 40miles-2gallons (2, 40) and point 0 (0, 0)

Now you will need to remember the slope formula which is:

$m=\frac{y_2-y_1}{x_1-x_2}$

so your point (x1, y1) will be (0, 0)

and point (x2, y2) will be (2, 40)

so $m=\frac{40-0}{2-0}$

which is $m=\frac {40}{2} = 20$

and so you get that the slope will be 20 miles/gallon

For graph B, what they want you to see is that change of y/change of x means the same as change of miles/change of gallons since x is the gallons and y is the miles.

8 0

3 years ago

5. Show that the following points are collinear. a) (1, 2), (4, 5), (8,9)

Irina-Kira [14]

Label the points A,B,C

A = (1,2)
B = (4,5)
C = (8,9)

Let's find the distance from A to B, aka find the length of segment AB.

We use the distance formula.

$A = (x_1,y_1) = (1,2) \text{ and } B = (x_2, y_2) = (4,5)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(1-4)^2 + (2-5)^2}\\\\d = \sqrt{(-3)^2 + (-3)^2}\\\\d = \sqrt{9 + 9}\\\\d = \sqrt{18}\\\\d = \sqrt{9*2}\\\\d = \sqrt{9}*\sqrt{2}\\\\d = 3\sqrt{2}\\\\$

Segment AB is exactly $3\sqrt{2}$ units long.

Now let's find the distance from B to C

$B = (x_1,y_1) = (4,5) \text{ and } C = (x_2, y_2) = (8,9)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(4-8)^2 + (5-9)^2}\\\\d = \sqrt{(-4)^2 + (-4)^2}\\\\d = \sqrt{16 + 16}\\\\d = \sqrt{32}\\\\d = \sqrt{16*2}\\\\d = \sqrt{16}*\sqrt{2}\\\\d = 4\sqrt{2}\\\\$

Segment BC is exactly $4\sqrt{2}$ units long.

Adding these segments gives

$AB+BC = 3\sqrt{2}+4\sqrt{2} = 7\sqrt{2}$

----------------------

Now if A,B,C are collinear then AB+BC should get the length of AC.

AB+BC = AC

Let's calculate the distance from A to C

$A = (x_1,y_1) = (1,2) \text{ and } C = (x_2, y_2) = (8,9)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(1-8)^2 + (2-9)^2}\\\\d = \sqrt{(-7)^2 + (-7)^2}\\\\d = \sqrt{49 + 49}\\\\d = \sqrt{98}\\\\d = \sqrt{49*2}\\\\d = \sqrt{49}*\sqrt{2}\\\\d = 7\sqrt{2}\\\\$