Answer:
Mr. Chang will have 15714.90 dollars.
Step-by-step explanation:
p = 650
r = 
Number of periods or n = 
Future value formula is : ![p[\frac{(1+r)^{n}-1}{r} ]](https://tex.z-dn.net/?f=p%5B%5Cfrac%7B%281%2Br%29%5E%7Bn%7D-1%7D%7Br%7D%20%5D)
Putting the values in formula we get;
![650[\frac{(1+0.0195)^{20}-1}{0.0195} ]](https://tex.z-dn.net/?f=650%5B%5Cfrac%7B%281%2B0.0195%29%5E%7B20%7D-1%7D%7B0.0195%7D%20%5D)
= $15714.90
Hence, Mr. Chang will have 15714.90 dollars.
Answer:
Transformation 3 across to the right and -7 down.
Answer:
10%
Step-by-step explanation:
We have been given that the manager of a store orders model railroad sets that cost $390 and sells them for $429.
We will use markup % formula for our given problem.





Therefore, markup is 10% of cost.
Answer
-1
Step-by-step explanation: