Recall the sum identity for cosine:
cos(a + b) = cos(a) cos(b) - sin(a) sin(b)
so that
cos(a + b) = 12/13 cos(a) - 8/17 sin(b)
Since both a and b terminate in the first quadrant, we know that both cos(a) and sin(b) are positive. Then using the Pythagorean identity,
cos²(a) + sin²(a) = 1 ⇒ cos(a) = √(1 - sin²(a)) = 15/17
cos²(b) + sin²(b) = 1 ⇒ sin(b) = √(1 - cos²(b)) = 5/13
Then
cos(a + b) = 12/13 • 15/17 - 8/17 • 5/13 = 140/221
Answer:
Additive inverse of (5-6) is (6-5),
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So:
(5-6)+(6-5)=0
5-6+6-5=0
5-6=-6+5
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Left <--- -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6 ---> Right
Move 5 places to the right of -6 and you should land on -1.
Answer:
you can do it , you can solve it , if you will not learn no job no money so need to study :))
Step-by-step explanation:
hope it helps ;)))
Answer:
relative minimum would be your awnser
Answer:
q=-1
Step-by-step explanation:
.8-.4q=.2q+1.4
-.2q -.2q
.8-.6q=1.4
-.8 -.8
-.6q= 0.6
/-.6 /-.6
q= -1
