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3 years ago

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In the given figure, ABCD is a parallelogram. E is any point on AB. CB and DE are produced to meet at F. Prove that area of tria

ngle CEF = area of triangle BDF. if AB=EB, then area triangle BCE = area of triangle BDE = 1/4 area of parallelogram ABCD.

1 answer:

marysya [2.9K]3 years ago

5 0

Download Photomath they’ll help

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