In the given figure, ABCD is a parallelogram. E is any point on AB. CB and DE are produced to meet at F. Prove that area of tria
ngle CEF = area of triangle BDF. if AB=EB, then area triangle BCE = area of triangle BDE = 1/4 area of parallelogram ABCD.
1 answer:
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Answer:
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Step-by-step explanation:
6/9 x 3/8
6(3) /8(9)
= 18/72
18/18=1
72/18=4
= D.) 1/4
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Answer:
1. 3/10
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Step-by-step explanation:
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Step-by-step explanation:
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