Answer:
given A=103° , B=24°
In triangle ABC,
A+B+C=180° [angle sum property of triangle]
103°+24°+C=180°
127°+C=180°
C=180°-127°
C=53°
hope it help u dear...
Attached solution with detailed work.
no solution.
The two lines are parallel
(same slope but different y intercepts)
(7t-2) - (-3t+1) = -3*(1-3t)
First distribute:
7t-2+3t-1 = -3+9t
Now get all the terms with 't' on the same side by subtracting/adding:
7t+3t-9t = -3+2+1
Combine the terms:
1t=0
t=0
Check:
Plug in 0 for t and see if both sides of the equation come out the same:
Does (7(0)-2) - (-3(0)+1) = -3(1-3(0)) ?
(-2) - (1) = -3(1) ?
-3 = -3 ?
Yes! It works, so t=0!
Answer:
=3.162
Step-by-step explanation:
x2
= −0 + √ 02 − 4×1×(−10)
2×1
= 0 + 2 × √ 10
2
= 3.162
