Hello
f(x) = 2sin(x)
f(<span>π/6) = 1
f'(x) 2cos(x)
f'(</span>π/6) = 2×co(π/6) = 2 × root(3)×0.5 =root(3)
The equation of this tangent line is : y= root(3)(x-π/6)+1
y = root(3)x+1 - π/6(root(x)) <span>in the form y=mx+b
m = root(3) and b = </span>1 - π/6(root(x))
We need to work out first the scale factor of the side length
Side MN correspond to the side JK
Side MN = 3.5 cm
Side JK = 14 cm
Scale factor = 14/3.5 = 4
Side OM correspond to side LJ
Side OM = 12 cm
Side LJ = 12 × 4 = 48 cm
Answer:
slope is 1/5
Step-by-step explanation:
Count how far right the point goes=1
count how far up the point goes =5
There are no steps to show, you just have to know which part of the equation effects which part of the graph:
Eqn. 5 matches b (since there were absolutely no translations)
Eqn. 6 matches d (since there was a vertical translation of one upwards)
Eqn. 7 matches a (since there was a horizontal translation of one to the right)
Eqn. 8 matches c (since there was a reflection upon the y-axis and a vertical translation of two downwards)
Answer:
$9
Step-by-step explanation:
set up a proportion where 20% is represented as 20/100 and set it equal to 1.80/x
cross multiply and you should get 180=20x
divide by 20 to solve for x
you then get 9, which is the amount you were looking for
