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blsea [12.9K]
3 years ago
6

Can someone please answer this ASAP??

Mathematics
1 answer:
loris [4]3 years ago
5 0
V=πr²h/3
Diameter is 24ft, Radius = 12 ft 
V=π12²10/3≈1507.96
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When baking a cake you have a choice of the following pans: a round cake that is 2 inches deep and has a 7-inch diameter, a 6 in
irga5000 [103]
The answer is
round cake - 82.42 in²
rectangular cake - 114 in²

Round cake:
d = 7 in
r = d/2 = 7 in / 2 = 3.5 in
h = 2 in

The surface are of a cylinder is:
A = 2πr² + 2πrh

The surface are of the round cake (which is actually a cylindrical cake) excluding the bottom is:
A = 2πr² + 2πrh - πr²
A = πr² + 2πrh
A = 3.14 * 3.5² + 2 * 3.14 * 3.5 * 2
    = 38.46 + 43.96
    = 82.42 in²

Rectangular cake:
w = 6 in
l = 9 in
h = 2 in

The surface are of a rectangle is:
A = 2wl + 2wh + 2lh

The surface are of the rectangular cake excluding the bottom is:
A = 2wl + 2wh + 2lh - wl
A = wl + 2wh + 2lh
A = 6 * 9 + 2 * 6 * 2 + 2 * 9 * 2
    = 54 + 24 + 36
    = 114 in²

5 0
3 years ago
Let (-5,-4) be a point on the terminal side of (theta). Find the exact values of cos, csc, and tan.
Rasek [7]

The exact values of the trigonometric identities cos, csc and tan as required in the task content are; -√41/5, -√41/4 and 4/5 respectively.

<h3>What are the exact values of cos, csc and tan as required in the task content?</h3>

It follows from above that the terminal side of the angle theta as described is on the point with coordinates (-5, -4).

Hence, the points spans 5 units leftwards and r units downwards on x and y axis respectively.

Hence, the length of the line that describes the angle by Pythagoras theorem is;

h = √((-4)² + (-5)²)

h = √41.

Hence, it follows from trigonometric identities that;

Cos (theta) = -5/√41.

Csc (theta) = -√41/4

Tan (theta) = 4/5

Read more on trigonometric identities;

brainly.com/question/24496175

#SPJ1

3 0
1 year ago
Strontium-90 has a half-life of 28.8 years. If you start with a 300-gram sample of strontium-90,
Kazeer [188]

Answer:  2.66 × 10⁻¹³

<u>Step-by-step explanation:</u>

First, use the decay formula   A=A_oe^{kt}   where

  • A is the final amount (amount left)
  • A₀ is the initial amount (amount you started with)
  • k is the rate of decay (you need to solve for this)
  • t is the time

Given:

  • A = 1/2(300) = 150
  • A₀ = 300
  • k = unknown
  • t = 28.8

150=300e^{28.8k}\\\\0.5=e^{28.8k}\\\\ln(0.5)=ln(e^{28.8k})\\\\ln(0.5)=28.8k\\\\\\\dfrac{ln(0.5)}{28.8}=k\\\\\\\large\boxed{-0.0240676=k}\\

Next, input the k-value and the new t-value to solve for A.

  • A = unknown
  • A₀ = 300
  • k = -0.0240676
  • t = 1440

A=300e^{1440(-.0240676)}\\\\\large\boxed{A=2.66\times 10^{-13}}\\

5 0
3 years ago
A skydiver in a computer game free-falls from a height of 3000 meters at a
mylen [45]
H= -55t + 3000. Hope this helps!
8 0
2 years ago
Find the nth term of a gp with (a. find term = 5, common ratio = 2​
Rina8888 [55]

Step-by-step explanation:

we know,

tn= a {(r)}^{n - 1}  \\ T5 = a {(2)}^{5 - 1}  \\ t5 = a \times  {2}^{4}  \\  = 16a

Therefore, nth term of a given gp is

16a

7 0
3 years ago
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