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2 years ago

4. Tom bought 333 pounds of

Mathematics

1 answer:

Lady_Fox [76]2 years ago

8 0

Tom bought 768 pounds of candy because 333 + 435 = 768

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Bobby has 20 cubic feet of toys! His parents

GarryVolchara [31]

2 feet is the minimum height it can be

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2 years ago

Highlight three ordered pairs that will form a relation with a range of {-3, 4, 7}.

sdas [7]

Answer:

826

Step-by-step explanation:

8e xhjdndd dd

dgsjsj

3 0

2 years ago

Use the fundamental theorem of calculus to find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x

BaLLatris [955]

Answer:

The area of the region is 25,351 $units^2$ .

Step-by-step explanation:

The Fundamental Theorem of Calculus: if $f$ is a continuous function on $[a,b]$ , then

$\int_{a}^{b} f(x)dx = F(b) - F(a) = F(x) | {_a^b}$

where $F$ is an antiderivative of $f$ .

A function $F$ is an antiderivative of the function $f$ if

$F^{'}(x)=f(x)$

The theorem relates differential and integral calculus, and tells us how we can find the area under a curve using antidifferentiation.

To find the area of the region between the graph of the function $x^5 + 8x^4 + 2x^2 + 5x + 15$ and the x-axis on the interval [-6, 6] you must:

Apply the Fundamental Theorem of Calculus

$\int _{-6}^6(x^5+8x^4+2x^2+5x+15)dx$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int _{-6}^6x^5dx+\int _{-6}^68x^4dx+\int _{-6}^62x^2dx+\int _{-6}^65xdx+\int _{-6}^615dx$

$\int _{-6}^6x^5dx=0\\\\\int _{-6}^68x^4dx=\frac{124416}{5}\\\\\int _{-6}^62x^2dx=288\\\\\int _{-6}^65xdx=0\\\\\int _{-6}^615dx=180\\\\0+\frac{124416}{5}+288+0+18\\\\\frac{126756}{5}\approx 25351.2$

3 0

3 years ago

The remainder obtained when 3x^3 - 6x^2 + ax -1 is divided by x+1 is equal to the remainder obtained when the same expression is

telo118 [61]

Answer:

Step-by-step explanation:

Solution

verified

Verified by Toppr

We have x

−ax

+6x−a

Apply remainder theorem

x−a=0

x=a

Put x=a in equation.

(a)

−a(a)

+6a−a

−a

+6a−a

=6a−a

=5a

Then reminder is 5a

4 0

2 years ago

BC = 36; D = 15. What is the value of BD - AC. B A BD - AC =

Snezhnost [94]

Answer:

BD - AC = 0

Step-by-step explanation:

Given that:

BC = 36 , CD = 15 and BD = x

As these are forming right angled triangle,

Using Pythagorean theorem,

$(BD)^2+(CD)^2=x^2\\(36)^2+(15)^2 = x^2\\1296 + 225 = x^2\\1521 = x^2\\$

Taking square root on both sides

$\sqrt{x^2}=\sqrt{1521}\\x=39$

As the given shape is rectangular, the sides parallel to each other will have same values.

AB = 15 , AD = 36 and AC = x

$(15)^2+(36)^2 = x^2 \\225 + 1296 = x^2 \\1521 = x^2 \\x = 39$

Now,

BD - AC = 39 - 39 = 0

Hence,

BD - AC = 0

5 0

3 years ago