Sphere A has a radius of 24 centimeters, and sphere B has a diameter of 42 centimeters. The radius of sphere A is multiplied by
2 answers:
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Check the picture below.
so, to get the area of the triangles, we can simply run a perpendicular line from the top to the base, and end up with a right-triangle with a base of 22 and a hypotenuse of 34, let's find the altitude.
so then the surface area of the triangular prism is,
![\bf \stackrel{\textit{left and right}}{2(34\cdot 76)}~~+~~\stackrel{\textit{bottom}}{(44\cdot 76)}~~+~~\stackrel{\textit{front and back}}{2\left[\cfrac{1}{2}(44)(\sqrt{672}) \right]} \\\\\\ 8512~~+~~(44)(\sqrt{672})\qquad \approx\qquad 9652.61036291978](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bleft%20and%20right%7D%7D%7B2%2834%5Ccdot%2076%29%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Bbottom%7D%7D%7B%2844%5Ccdot%2076%29%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Bfront%20and%20back%7D%7D%7B2%5Cleft%5B%5Ccfrac%7B1%7D%7B2%7D%2844%29%28%5Csqrt%7B672%7D%29%20%20%5Cright%5D%7D%0A%5C%5C%5C%5C%5C%5C%0A8512~~%2B~~%2844%29%28%5Csqrt%7B672%7D%29%5Cqquad%20%5Capprox%5Cqquad%209652.61036291978)
so, to get the area of the triangles, we can simply run a perpendicular line from the top to the base, and end up with a right-triangle with a base of 22 and a hypotenuse of 34, let's find the altitude.
so then the surface area of the triangular prism is,
Answer:
First: 15
Second: 21
Third: 45
Step-by-step explanation:
In order to create the equation we need to represent the evenings with an alebraic term, in thsi case we are going to represent the second evening with an X
Second evening:x
The first night she got 6 fewer calls than the second: Second-6=x-6
The third night she received 3 times the first: 3(first night)=3(x-6)
The equation is First Night plus second night plus third night equals 81.
So the first evening he received 15 calls, the second he received 21 and the third one he received 45.