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SSSSS [86.1K]
3 years ago
14

Plz help me!!! Giving brainliest if someone else answers it. I put 2 questions

Mathematics
1 answer:
Katarina [22]3 years ago
6 0

Answer:

1) C

2) A

Hope it Helps!

:)

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The number 10 lies between what two integers?
EleoNora [17]

Answer:

9 and 11

Step-by-step explanation:

9 and 11 are before and after 10. so, 10 lies between them.

5 0
3 years ago
The length of a rectangle is 5.4 cm more than 2 times the width. If the perimeter of the rectangle is 39.6 cm, what are its dime
ale4655 [162]

Answer:

Step-by-step explanation:

vdvfdvfdvfvfb fd

8 0
2 years ago
(42) A school only provides bus service
Nostrana [21]

Answer:

~1.8 mile

Step-by-step explanation:

Michael lives at the closest  point to the school (the origin) on Maple Street,  which can be represented by the line  y = 2x – 4.

This means Michael's house will be the intersection point of line y1 (y = 2x - 4) and line y2 that is perpendicular to y1 and passes the origin.

Denote equation of y2 is y = ax + b,

with a is equal to negative reciprocal of 2 => a = -1/2

y2 pass the origin (0, 0) => b = 0

=> Equation of y2:

y = (-1/2)x

To find location of Michael's house, we get y1 = y2 or:

     2x - 4 = (-1/2)x

<=> 4x - 8 = -x

<=> 5x = 8

<=> x = 8/5

=> y = (-1/2)x = (-1/2)(8/5) = -4/5

=> Location of Michael' house: (x, y) = (8/5, -4/5)

Distance from Michael's house to school is:

D = sqrt(x^2 + y^2) = sqrt[(8/5)^2 + (-4/5)^2) =  ~1.8 (mile)

4 0
3 years ago
Toilet Training You are a great friend and are taking your friend's child to the playground to play with two of his friends: Cha
Brilliant_brown [7]

Answer:

Step-by-step explanation:

Hello!

According to a study regarding the average age of female and male kids to complete toilet training is:

Females:

Average age 32.5 months

The standard deviation of 6.7 months

n= 126

Males:

Average age 35.0 months

The standard deviation of 10.1 months

n= 141

The parameter of study is the difference between the age of females are successfully toilet trained and the average age that males are successfully toilet trained. μf - μm (f= female and m= male)

a.

Assuming that both variables have a normal distribution to choose whether you'll use an unpooled or pooled-t to calculate the confidence interval you have to conduct an F-test for variance homogeneity.

If the variances are equal, then you can usee the pooled-t, but if the variances are different, you have to uses Wlche's approach:

H₀: δ²f = δ²m

H₁: δ²f ≠ δ²m

Since both items b. and c. ask for a 95% CI I'll use the complementary significance level for this test:

α: 0.05

F= \frac{S^2_f}{S^2_m} * \frac{xSigma^2_f}{Sigma^2_m} ~~~F_{(n_f-1); (n_m-1)}

F= \frac{(6.7^2)}{(10.1)^2} *1= 0.44

Critical values:

F_{125;140;0.025}= 0.71\\F_{125;140;0.975}= 1.41

The calculated F value is less than the lower critical value, 0.77, so the decision is to reject the null hypothesis. In other words, there is no significant evidence to conclude the population variances of the age kids are toilet trained to be equal. You should use Welch's approach to construct the Confidence Intervals.

Df_w= \frac{(\frac{S^2_f}{n_f} + \frac{S^2_m}{n_m} )^2}{\frac{(\frac{S^2_f}{n_f} )^2}{n_f-1} +\frac{(\frac{S^2_m}{n_m} )^2}{n_m-1} }

Df_w= \frac{(\frac{6.7^2}{126} + \frac{10.1^2_m}{141} )^2}{\frac{(\frac{126^2}{126} )^2}{126-1} +\frac{(\frac{10.1^2}{141} )^2}{141-1} } = 254.32

b.

The given interval is:

[0.3627; 4.6073]

Using Welch's approach, the formula for the CI is:

(X[bar]f- X[bar]m) ± t_{Df_w;1-\alpha /2} * \sqrt{\frac{S^2_f}{n_f} +\frac{S^2_m}{n_m} }

or

(X[bar]m- X[bar]f) ± t_{Df_w;1-\alpha /2} * \sqrt{\frac{S^2_f}{n_f} +\frac{S^2_m}{n_m} }

As you can see either way you calculate the interval, it is centered in the difference between the two sample means, so you can clear the value of that difference by:

(Upper bond - Lower bond)/2= (4.6073-0.3627)/2= 2.1223

The average age for females is 32.5 months and for males, it is 35 months.

Since the difference between the sample means is positive, we can say that the boys were considered "group 1" and the girls were considered "group 2"

You have a95% confidence that the parameter of interest is included in the given confidence interval.

c.

None of the statements is correct, the interval gives you information about the difference between the average age the kids are toilet trained, that is between the expected ages for the entire population of male and female babies.

This represents a guideline but is not necessarily true to all individuals of the population since some male babies can be toilet trained before that is expected as some female babies can be toiled trained after the average value.

I hope it helps!

6 0
3 years ago
I am thinking of a number
valkas [14]

Answer:

1422

Step-by-step explanation:

calculated sooo yerp

7 0
2 years ago
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