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3 years ago

20 area and 4 is the height what is the base

Mathematics

2 answers:

ohaa [14]3 years ago

7 0

5 because area=base x height

notsponge [240]3 years ago

6 0

The base is 5 because 4×5 is 20

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A tree trunk has a diameter 50cm and a height 7.9m.

____ [38]

Answer:

Ratio = 5:79.

Step-by-step explanation:

Convert the height to cms:

Height of the tree = 7.9 * 100 = 790 cm

Ratio = 50 : 790

Divide both values by 10;

Ratio = 5:79.

8 0

4 years ago

Solve for system of equations y = - 5/4x - 2 and y = -1/4x + 19

MariettaO [177]

Answer:

x = -21

Step-by-step explanation:

-5/4x - 2 = -1/4x + 19

subrtact the slope( constant, mx) from both sides

subtract a y-int ftom both sides

divde both sides by the remaining slope(constant or mx)

7 0

3 years ago

Which expression is equivalent to 14y−12?

Anettt [7]

Answer:

The answer is 1/4 (y-2)

Step-by-step explanation:

I got the answer correct on my test!

7 0

3 years ago

I need help in partial fraction!! With simple explaination would be nice!

WITCHER [35]

$\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}$

The degree of the numerator (4) is larger than the degree of the denominator (3), so first you need to divide. (Added screenshot of long division procedure.)

$\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}=x-\dfrac{4x^2-17x+10}{x(x^2-3)}$

Now the second term can be decomposed into partial fractions.

$\dfrac{4x^2-17x+10}{x(x^2-3)}=\dfrac{r_1}x+\dfrac{r_2x+r_3}{x^2-3}$
$\dfrac{4x^2-17x+10}{x(x^2-3)}=\dfrac{r_1(x^2-3)+x(r_2x+r_3)}{x(x^2-3)}$
$4x^2-17x+10=r_1(x^2-3)+x(r_2x+r_3)$
$4x^2-17x+10=(r_1+r_2)x^2+r_3x-3r_1$
$\implies\begin{cases}r_1+r_2=4\\r_3=-17\\-3r_1=10\end{cases}\implies r_1=-\dfrac{10}3,r_2=\dfrac{22}3,r_3=-17=-\dfrac{51}3$
$\implies\dfrac{4x^2-17x+10}{x(x^2-3)}=-\dfrac{10}{3x}+\dfrac{22x-51}{x^2-3}$

So

$\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}=x+\dfrac{10}{3x}-\dfrac{22x-51}{x^2-3}$

3 0

3 years ago

Let(-8,3) be a point on the terminal side of theta . Find the exact values of sin theta ,csc theta , and cot theta sin theta = c

Marizza181 [45]

When we draw the terminal side in a Cartesian plane, this side is located at quadrant 1. We have to solve angle theta in order to obtain the trigonometric functions. First, we solve the angle in the triangle formed of the terminal side.

tan alpha = 3/8
alpha = 20.56°
theta = 180° - 20.56° = 159.44°

<span>sin theta =0.35
csc theta =2.85
<span>cot theta = -8/3</span></span>

8 0

4 years ago