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Ksju [112]
3 years ago
13

What is the value of [(2/3)^0]^-3

Mathematics
1 answer:
o-na [289]3 years ago
5 0

Answer:

1

Step-by-step explanation:

Easy because whenever the exponent is 0 the answer must always be 1 then the exponent on the outside it would still be 1.

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Easy! please help! <br><br> 17% is equivalent to? A. 17/100, B. 17 to 100 C. 17:100
nika2105 [10]
The answer is a obviously
3 0
3 years ago
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Sombody is taking a 1680 mile road trip. At the end of the first day they had completed 3/8of there trip. How many miles did the
patriot [66]

Answer:

Step-by-step explanation:

1680 mile road trip....they completed 3/8 of it...

so we need to figure 3/8 of 1680

" of " in math language means multiply

3/8 * 1680 = 5040/8 = 630 miles <===

7 0
3 years ago
30% of___ is 15 ?????
tensa zangetsu [6.8K]

Answer:

15 is 30% of 50

Step-by-step explanation:

We have, 30% × x = 15

Multiplying both sides by 100 and dividing both sides by 30,

we have x = 15 × 100/30

x = 50

If you are using a calculator, simply enter 15×100÷30, which will give you the answer.

7 0
3 years ago
The length of an object's shadow varies directly with It's heigt. If a can is 13 cm tall casts a shadow that is 7.5 cm long, a b
svetoff [14.1K]
X = Can/Bottle height, y = Shadow length
x = 13 cm, y = 7.5 cm
x = 2.5 cm, y = 14.2 cm
I'm assuming your question is asking for an equation to model this. Since there are only two data points the only equation that can be made is linear
y = mx + c
m = (y2 - y1)/(x2 - x1) <- Let 14.2 be y2, and 2.5 be x2 (it is important)
m = (14.2 - 7.5)/(2.5 - 13)
m = 6.7/-10.5
m = -0.638
y = -0.638x + c
To find c we can sub any one of the two coordinates, 
i'm choosing (2.5,14.2)
14.2 = -0.638(2.5) + c
14.2 = -1.595 + c
14.2 + 1.595 = c
15.795 = c
So the final equation is y = -0.638x + 15.795
6 0
3 years ago
Solution of 4/5 + 2/3
xxMikexx [17]

Answer:

\frac{22}{15}

Step-by-step explanation:

\frac{4}{5}+\frac{2}{3}

Adjust based on LCM (15):

=\frac{12}{15}+\frac{10}{15}

=\frac{12+10}{15}

=\frac{22}{15}

8 0
3 years ago
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