Question

I will give the brainliest

Answer 1

For this case we must find the hypotenuse (H) or the BC side of the rectangular triangle shown in the figure.

We have to:

$Tangent (B) = \frac {Cathet \ opposite} {Cathet \ adjacent}\\Tangent (45) = \frac {11} {BA}$

By clearing BA we have:

$BA = \frac {11} {Tangent (45)}\\BA = \frac {11} {1}\\BA = 11$

The Pythagorean theorem, which states:

$BC = \sqrt {(CA) ^ 2 + (BA) ^ 2}\\BC = \sqrt {(11) ^ 2 + (11) ^ 2}\\BC = \sqrt {(11) ^ 2 + (11) ^ 2}\\BC = \sqrt {2 * 11 ^ 2}\\BC = 11 \sqrt {2}$

Answer:

$BC = 11 \sqrt {2}$

Option C

Answer 2

Answer:

option 3

Step-by-step explanation:

sin45° = 11/BC

=>1/√2 = 11/BC

=>BC = 11√2