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zzz [600]
3 years ago
7

What is true of the data in the dot plot? Check all that apply. Number of Minutes for Each Commercial Break A dot plot going fro

m 1 to 5. 1 has 3 dots, 2 has 0 dots, 3 has 8 dots, 4 has 0 dots, and 5 has 3 dots. The center is 3. The peak is 5. There are no gaps. It is symmetric. It is skewed right. The spread is from 1 to 5. There were 14 commercial breaks.
Mathematics
1 answer:
Natasha2012 [34]3 years ago
5 0

Answer:

The center is 3

The peak is 5

The spread is from 1 to 5.

There were 14 commercial breaks.

Step-by-step explanation:

Edg

You might be interested in
Evaluate the numerical expression of 27 + 5 × 6
sesenic [268]
You have to use PEMDAS, by multiplying before you add. So when you multiply 5*6, you get 30 and add the remaining 27 to get 57.
4 0
3 years ago
Please help I don’t understand how to do this
horsena [70]

Answer:

DOC = 70

BOC = 110

AOD = 110

Step-by-step explanation:

AOB is supplementary to BOC and AOD, which means together they equal 180. 180-70=110, so BOC and AOD are both 110.

AOB and DOC are vertical angles to each other, so are AOD and BOC. Vertical angles are always equal to each other. So since AOB is 70, so is DOC.

Hope this makes sense:)

5 0
3 years ago
The following data comparing wait times at two rides at Disney are listed below: Position Pirates Splash Mountain Sample Size 32
myrzilka [38]

Answer:

a) (14.68 -18.77) - 2.39 \sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}} =-12.968

(14.68 -18.77) + 2.39 \sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}} =4.788

b) t=\frac{14.68-18.77}{\sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}}}}=-1.10  

Step-by-step explanation:

Data given and notation

\bar X_{A}=14.68 represent the mean for Pirates

\bar X_{B}=18.77 represent the mean for Splash Mountain

s_{A}=11.87 represent the sample standard deviation for the sample Pirates

s_{B}=16.79 represent the sample standard deviation for the sample Slpash Mountain

n_{A}=32 sample size selected for Pirates

n_{B}=30 sample size selected for Splash Mountain

\alpha=0.02 represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

p_v represent the p value for the test (variable of interest)

Part a

The confidence interval would be given by:

(\bar X_A -\bar X_B) \pm t_{\alpha/2} \sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}

The degrees of freedom are given by:

df = n_A +n_B -2 = 32+30-2 = 60

Since we want 98% of confidence the significance level is \alpha =1-0.98 =0.02 and \alpha/2 =0.01, we can find in the t distribution with df =60 a critical value that accumulates 0.01 of the area on each tail and we got:

t_{\alpha/2}= 2.39

And replacing we got for the confidence interval:

(14.68 -18.77) - 2.39 \sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}} =-12.968

(14.68 -18.77) + 2.39 \sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}} =4.788

Part b

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the means are equal, the system of hypothesis would be:

Null hypothesis:\mu_{A} = \mu_{B}

Alternative hypothesis:\mu_{A} \neq \mu_{B}

the statistic is given by:

t=\frac{\bar X_{A}-\bar X_{B}}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}} (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

t=\frac{14.68-18.77}{\sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}}}}=-1.10  

6 0
3 years ago
-3x+4=-17<br>show how you did it
Oxana [17]
-3x+4=-17
subtract -4 from both sides
divide -3 from both sides
the answer is 7
8 0
3 years ago
What is this answer?
zhuklara [117]

Answer:

B is the correct answer

3 0
3 years ago
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