1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
likoan [24]
3 years ago
5

Ba - ha = c solve for a

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
7 0

Answer:

h = \frac{c}{b-h}

Step-by-step explanation:

Given

ba - ha = c ← factor out a from each term on the left side

a(b - h) = c ← divide both sides by (b - h)

a = \frac{c}{b-h}

You might be interested in
Weights measured in grams of randomly selected M&M plain candies:
charle [14.2K]

Answer:

The range of weights of the middle 99.7% of M&M’s is between 0.8187 and 1.0203.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

Sample mean:

\overline{x} = \frac{0.957 + 0.912 + 0.925 + 0.886 + 0.920 + 0.958 + 0.915 + 0.914 + 0.947 + 0.939 + 0.842}{11} =  0.9195

Sample standard deviation:

s = \sqrt{\frac{(0.957-0.9195)^2 + (0.912-0.9195)^2 + (0.925-0.9195)^2 + (0.886-0.9195)^2 + ...}{10}} = 0.0336

What is the range of weights of the middle 99.7% of M&M’s?

By the Empirical Rule, within 3 standard deviations of the mean, so:

0.9195 - 3*0.0336 = 0.8187.

0.9195 + 3*0.0336 = 1.0203.

The range of weights of the middle 99.7% of M&M’s is between 0.8187 and 1.0203.

6 0
3 years ago
Kim and Rachel are creating patterns.
jonny [76]
The answer that appears first is 7
6 0
3 years ago
HELP AS FAST AS U CAN!
OlgaM077 [116]

Answer:

A- 2x + 8

Step-by-step explanation:

Combine like terms

6x - 4x = 2x. 2x + 8 is left

6 0
3 years ago
Read 2 more answers
Roger owns a one-acre piece of land. The length of the land is 484 feet. What is the width of his property?
shepuryov [24]

Answer:

W = 90 ft

Step-by-step explanation:

1 acre = 43,560 ft^2

A (area) = L (length) x W (width),

L = 484

A = 43560

W = A/L

= 43560/484

= 90 ft

8 0
3 years ago
QUESTION 4 If 1 foot = 0.37 metres and 1 mile = 5,180 feet, find the number of kilometres in 15 miles. show how to work out the
Andreas93 [3]

Answer:

28.749 km

Step-by-step explanation:

in reality

1 foot = 0.3048 meters not 0.37

1 mile = 5,280 feet not 5,180

15 miles  = 24.14016 kilometers

---------------------------

Using the numbers stated in the problem

0.37m/ft * 5180ft/mile * 15mile * 1km/1000m = 28.749 km

4 0
2 years ago
Other questions:
  • Alaine has 1 gallon of paint. She is going to pour it into a paint tray that measures 10 inches wide, 12 inches long, and 5 cm d
    11·1 answer
  • How is a rational number that is not an integer different from a rational number that is an integer?
    6·1 answer
  • Paige
    5·2 answers
  • A line perpendicular to y=1/4x+3 passes through the point (0,6). Which other point lies on the line
    6·1 answer
  • What is the sum? –50+18<br> a. –68<br> b. –32<br> c. 32<br> d. 68
    10·2 answers
  • Find the volume of the rectangular pyramid please help me guys
    8·2 answers
  • For all values of x, f(x)=x-1 and g(x)=2x^2+3. Solve fg(x)=gf(x)
    11·1 answer
  • HELP ASAP ! PLEASE I LOVE YOU MAY GOD BLESS YOU &lt;3 :)
    5·2 answers
  • Some red, white, and blue candies were placed in a bowl. Some contain nuts, and some do not. Suppose one of the candies were cho
    6·1 answer
  • Alaina bought a square frame for her desk that has an area of 81 square inches. What is the perimeter of the frame?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!