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SOVA2 [1]
3 years ago
15

Amanda surveyed 13 students in her class about their heights in inches. Her data are listed below: 58, 59, 55, 52, 57, 59, 62, 5

8, 55, 56, 59, 65, 53
What is the IQR of this data set?
What is the Median (Q2) of this data set?
Mathematics
2 answers:
Anton [14]3 years ago
6 0
Iqr is 4, median is 58 hope that answers your question.
Aleonysh [2.5K]3 years ago
3 0

Answer:

IQR is 4, median is 58.

Step-by-step explanation:

Enter these values in a list, hit stat > calc > 1-var stats. That gives you the 5 number summary. To get IQR, subtract Q3 from Q1.

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Please solve these 2 ;-;<br><br> y = 2x – 6<br> y = –4x + 3
Yuri [45]

Answer:

x = 3/2 | y = -3

Step-by-step explanation:

Given equations:

  • y = 2x - 6. . . .(i)
  • y = -4x + 3. . . . (ii)

Substituting from equation (i) for y:

==> 2x - 6 = -4x + 3

==> 2x + 4x = 6 + 3

==> 6x = 9

<em>dividing both </em><em>sides by 3</em><em>:</em>

==> 2x = 3

==> x = 3/2

Substituting 3/2 for x in equation (i):

==> y = 2(3/2) - 6

==> y = 3 - 6

==> y = -3

3 0
3 years ago
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Find the value of z.
AVprozaik [17]

Answer:

  z = 110°

Step-by-step explanation:

Angles z and the one marked 70° form an linear pair, hence are supplementary.

  z = 180° -70° = 110°

<h3>Angles where chords cross</h3>

The angle made by two chords is half the sum of the arcs intercepted by those chords. Here, that means ...

  70° = 1/2(60° +x)   ⇒   x = 140° -60° = 80°

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  w +x +79° +60° = 360°   ⇒   w = 360° -219° = 141°

Finally, z is the average of w and 79°:

  z = (w +79°)/2 = (141° +79°)/2 = 110° . . . as above

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