The amount invested in the account that yields 7% interest is $4000.
The amount invested in the account that yields 12% interest is $1000.
<h3>What are the linear equations that represent the question?</h3>
a + b = 5000 equation 1
0.07a + 0.12b = 400 equation 2
Where:
a = amount invested in the account that yields 7% interest.
b = amount invested in the account that yields 12% interest.
<h3>How much is invested at each rate?</h3>
Multiply equation 1 by 0.07
0.07a + 0.07b = 350 equation 3
Subtract equation 3 from equation 2
0.05b = 50
b = 50 / 0.05
b = 1000
Subtract 1000 from 5000: 5000 - 1000 = 4000
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Answer:
7x+7y
Step-by-step explanation:
3x+3y+4y+4x
7x+7y
Answer:
the simple multiplier is equal to 4
Step-by-step explanation:
Given that:
Y= C + I + G + (X - M)
the average expenditure Y must be equal to the totality of the output
If C = 3 + 0.75Y
here;
the marginal propensity consumed MPC = 0.75
Then,
Y = 3 + 0.75Y + 2 + 1
Y = 6+0.75 Y
Y - 0.75 Y = 6
0.25 Y = 6
Y = 6/0.25
Y = 24
However, the simple multiplier can be expressed as:
=
= 4
(8x - 8y + 9) - (5x - 8y - z) = 3x + z + 9
8 - 5 = 3
-8 - (-8) = 0
9 - 0 =9
0 - (-z) = z
so it is written 3x +z +9
The speed ratio of the two trains is 4:3, that is, for every 4 hours that one train is delayed, the other is delayed 3.
<h3>How to find the speed ratio of the trains?</h3>
To find the speed ratio of the trains we must do the following operation:
- V1 =
- V1 =
- T =
- V2 =
- V1 : V2 = :
Note: This question is incomplete because there is some information missing. Here is the complete information in:
A train started from Howrah for Allahabad another train started from Allahabad for Howrah at the same time. The two trains reached their destinations in 9hours and 16 hours respectively after they meet each other. Find the ratio of speed of the two trains.
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