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tekilochka [14]
3 years ago
6

C(t)=2(t-4)(t+1)(t-6)​

Mathematics
1 answer:
Licemer1 [7]3 years ago
3 0
Can y’all help me in my recent
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A) 12 x - 18 = 4x + 30​
olga55 [171]

Answer:

x = 6

Step-by-step explanation:

You add 18 to both sides so that the equation turns into 12x = 4x + 48

Then you subtract 4x from both sides so that the equation becomes 8x = 48

Then you divide both sides by 8 and get x = 6

3 0
3 years ago
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Using an appropriately designed and analyzed study, a researcher observes a p-value of 0.010000. Consider the following proposit
mafiozo [28]

Answer: a.

a. PROPOSITION ONE is true and PROPOSITION TWO is true

b. PROPOSITION ONE is true and PROPOSITION TWO is false

c. PROPOSITION ONE is false and PROPOSITION TWO is true

d. PROPOSITION ONE is false and PROPOSITION TWO is false

e. None of the above

7 0
3 years ago
Practice solving roblems involving the volume or
Effectus [21]

Answer:

V = 4.187r³

Step-by-step explanation:

Volume of a sphere is expressed using the formula;

V = 4/3πr³

r is the radius

Substitute π = 3.14 into the formula

V = 4/3 * 3.14r³

V = 4.187r³

Hence the volume of a sphere in terms of the radius is V = 4.187r³

3 0
3 years ago
A new company opens and finds the profits from their first year in business is $24,000. They project the company's profits to in
Fiesta28 [93]

Answer:

$4406.7 is the profit.

explanation:

compound interest formula: \sf \large\boxed{\sf P(1+\frac{r}{100})^n }

using this formula:

\rightarrow \ \sf \sf 24000(1+\dfrac{1.7}{100})^{10} }

\rightarrow \sf \ $ \sf 28406.7

profit: $28406.7  - $24,000 = $4406.7

8 0
3 years ago
In 2018, Mike Krzyewski and John Calipari topped the list of highest paid college basketball coaches (Sports Illustrated website
expeople1 [14]

From the data given, we estimate the population mean and population standard deviation. Then, we use this estimate to find a 95% confidence interval for the population variance and the population standard deviation.

Sample:

Salaries in millions of dollars: 2.2, 1.5, 0.5, 1.3, 2.4, 1.5, 2.7, 0.3, 2.0, 0.3

Question a:

The mean is the sum of all values divided by the number of values. So

\overline{x} = \frac{2.2 + 1.5 + 0.5 + 1.3 + 2.4 + 1.5 + 2.7 + 0.3 + 2.0 + 0.3}{10} = 1.42

The sample mean salary is of 1.42 million.

Question b:

The standard deviation is the square root of the difference squared between each value and the mean, divided by one less than the number of values.

So

s = \sqrt{\frac{(2.2-1.42)^2 + (1.5-1.42)^2 + (0.5-1.42)^2 + (1.3-1.42)^2 + (2.4-1.42)^2 + (1.5-1.42)^2 + (2.7-1.42)^2 + ...}{9}} = 0.8772

Thus, the estimate for the population standard deviation is of 0.8772 million.

Question c:

The sample size is n = 10

The significance level is \alpha = 1 - 0.05 = 0.95

The estimate, which is the sample standard deviation, is of s = 0.8772.

Now, we have to find the critical values for the Pearson distribution. They are:

\chi^2_{\frac{\alpha}{2},n-1} = \chi^2_{0.025,9} = 19.0228

\chi^2_{1-\frac{\alpha}{2},n-1} = \chi^2_{0.975,9} = 2.7004

The confidence interval for the population variance is:

\frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2},n-1}} < \sigma^2 < \frac{(n-1)s^2}{\chi^2_{1-\frac{\alpha}{2},n-1}}

\frac{9*0.8772^2}{19.0228} < \sigma^2 < \frac{9*0.8772^2}{2.7004}

0.3641 < \sigma^2 < 2.5646

Thus, the 95% confidence interval for the population variance is (0.3641, 2.5646)

Question d:

Standard deviation is the square root of variance, so:

\sqrt{0.3641} = 0.6034

\sqrt{2.5646} = 1.6014

The 95% confidence interval for the population standard deviation is (0.6034, 1.6014).

For more on confidence intervals for population mean/standard deviation, you can check brainly.com/question/13807706

4 0
3 years ago
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