E(X) = 0(0.7) + 1(0.2) + 2(0.1) = 0.2 + 0.2 = 0.4
The expected daily loss due to blackouts = 0.4 * $500 = $200
Var(X) = 0(0.7 - 0.4)^2 + 1(0.2 - 0.4)^2 + 2(0.1 - 0.4)^2 = 0.04 + 0.18 = 0.22
The expected daily variance due to blackouts = 0.22 * $500 = $110
I don't really understand your question , can you rephrase it ?
Do you mean ?5x7 = 455 ?
because then it would be :
455 divided by 7 which equals 65 :)
Answer:
The odds of an event happening depend on the situation so it is really difficult to tell what the odds would be.
Step-by-step explanation:
Erm I would say it comes from the same money pot (account) but not 100% sure what your tryin to ask
Answer:
NOt finished
Step-by-step explanation:
PAGE 1
1.) enlargement b/c the number is more that 1
2.) reduction b/c the number is less than 1
3.) enlargement b/c the number is more than 1
4.) reduction b/c the number is less than 1
5.) reduction k = 1/3
6.) enlargement k = 5/2 or 2.5
PAGE 2
7.) reduction k = 1/3
8.) enlargement k = 2
PAGE 3
Screen shot
PAGE 4
screen shot
PAGE 5
screen shot
I WILL DO THE SCREENSHOTS TOMORROW
