This is factoring trinomials,help plz!

Mathematics

1 answer:

MaRussiya [10]3 years ago

8 0

10.
Factor the following:
8 x^2 - 2 x - 10
Factor 2 out of 8 x^2 - 2 x - 10:
2 (4 x^2 - x - 5)

Factor the quadratic 4 x^2 - x - 5. The coefficient of x^2 is 4 and the constant term is -5. The product of 4 and -5 is -20. The factors of -20 which sum to -1 are 4 and -5. So 4 x^2 - x - 5 = 4 x^2 - 5 x + 4 x - 5 = 4 x (x + 1) - 5 (x + 1):
2 4 x (x + 1) - 5 (x + 1)
Factor x + 1 from 4 x (x + 1) - 5 (x + 1):
Answer: 2 (x + 1) (4 x - 5)
_____________________________________________

13.
Factor the following:
16 x^2 - 24 x + 8

Factor 8 out of 16 x^2 - 24 x + 8:
8 (2 x^2 - 3 x + 1)

Factor the quadratic 2 x^2 - 3 x + 1. The coefficient of x^2 is 2 and the constant term is 1. The product of 2 and 1 is 2. The factors of 2 which sum to -3 are -1 and -2. So 2 x^2 - 3 x + 1 = 2 x^2 - 2 x - x + 1 = -(2 x - 1) + x (2 x - 1):
8 x (2 x - 1) - (2 x - 1)

Factor 2 x - 1 from x (2 x - 1) - (2 x - 1):
Answer: 8 (2 x - 1) (x - 1)

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What is the area of an equilateral triangle with the base of 8 cm? Round your answer to the hundredths place.

Lady_Fox [76]

Step-by-step explanation:

$\frac{{x}^{2} \times \sqrt{3}}{4}$

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5 0

2 years ago

Read 2 more answers

PLEASE HELP precal!

sergij07 [2.7K]

Check the picture below

so.. .hmmm the vertex is at the origin... and we know the parabola passes through those two points... let's use either.. say hmmm 100,-50, to get the coefficient "a"

keep in mind that, the parabolic dome is vertical, thus we use the y = a(x-h)²+k version for parabolas, which is a vertical parabola

as opposed to x = (y-k)²+h, anyway, let's find "a"

$\bf y=a(x-0)^2+0\implies y=ax^2\qquad 
\begin{cases}
x=100\\
y=-50
\end{cases}\implies -50=a100^2
\\\\\\
\cfrac{-50}{100^2}=a\implies -\cfrac{1}{200}=a
\\\\\\
thus\qquad \qquad y=-\cfrac{1}{200}x^2\implies \boxed{y=-\cfrac{x^2}{200}}$

now.. .your choices, show.... a constant on the end.... a constant at the end, is just a vertical shift from the parent equation, the equation we've got above.. is just the parent equation, since we used the origin as the vertex, it has a vertical shift of 0, and thus no constant, but is basically, the same parabola, the one in the choices is just a shifted version, is all.