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sergey [27]
3 years ago
8

This is factoring trinomials,help plz!

Mathematics
1 answer:
MaRussiya [10]3 years ago
8 0
10.
Factor the following:
8 x^2 - 2 x - 10
Factor 2 out of 8 x^2 - 2 x - 10:
2 (4 x^2 - x - 5)

Factor the quadratic 4 x^2 - x - 5. The coefficient of x^2 is 4 and the constant term is -5. The product of 4 and -5 is -20. The factors of -20 which sum to -1 are 4 and -5. So 4 x^2 - x - 5 = 4 x^2 - 5 x + 4 x - 5 = 4 x (x + 1) - 5 (x + 1):
2 4 x (x + 1) - 5 (x + 1)
Factor x + 1 from 4 x (x + 1) - 5 (x + 1):
Answer:  2 (x + 1) (4 x - 5)
_____________________________________________

13. 
Factor the following:
16 x^2 - 24 x + 8

Factor 8 out of 16 x^2 - 24 x + 8:
8 (2 x^2 - 3 x + 1)

Factor the quadratic 2 x^2 - 3 x + 1. The coefficient of x^2 is 2 and the constant term is 1. The product of 2 and 1 is 2. The factors of 2 which sum to -3 are -1 and -2. So 2 x^2 - 3 x + 1 = 2 x^2 - 2 x - x + 1 = -(2 x - 1) + x (2 x - 1):
8 x (2 x - 1) - (2 x - 1)

Factor 2 x - 1 from x (2 x - 1) - (2 x - 1):
Answer: 8 (2 x - 1) (x - 1)
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11.Find the missing value given the rate of change.(2,6) and (x, 10) m = 4
Anvisha [2.4K]

The missing value x=3 is obtained by the concept of slope in coordinate geometry.

<h3>What is slope?</h3>

Positive or negative rates of change are both possible. Since the slope of a line is determined by the ratio of the vertical and horizontal change between any two locations on a plane or line, the slope is determined by the rise to run ratio. Where, Rise is the difference in elevation between two points. The horizontal shift between two places is known as a run.

Formula of slope = \frac{y2-y1}{x2-x1} (equation 1)

According to the question the coordinates are: xi=2, x2=x, y1=6, y2=10

Given, rate of change=4 (here rate of change=slope)

Putting all coordinates in equation 1

Slope= \frac{10-6}{x-2}

4=4/x-2

x-2=1

x=3

Therefore, the missing value x=3

To know more about slope visit:

brainly.com/question/3605446

#SPJ9

4 0
1 year ago
Need help ASAP ? <br>3/4×20
In-s [12.5K]

3/4 x 20

3/4 x 20/1

3 x 20 = 60

4 x 1 = 4

60 / 4 = 15

8 0
3 years ago
Read 2 more answers
(10 points) Consider the initial value problem y′+3y=9t,y(0)=7. Take the Laplace transform of both sides of the given differenti
Rashid [163]

Answer:

The solution

Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3 t}

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Consider the initial value problem y′+3 y=9 t,y(0)=7

<em>Step(i)</em>:-

Given differential problem

                           y′+3 y=9 t

<em>Take the Laplace transform of both sides of the differential equation</em>

                L( y′+3 y) = L(9 t)

 <em>Using Formula Transform of derivatives</em>

<em>                 L(y¹(t)) = s y⁻(s)-y(0)</em>

  <em>  By using Laplace transform formula</em>

<em>               </em>L(t) = \frac{1}{S^{2} }<em> </em>

<em>Step(ii):-</em>

Given

             L( y′(t)) + 3 L (y(t)) = 9 L( t)

            s y^{-} (s) - y(0) +  3y^{-}(s) = \frac{9}{s^{2} }

            s y^{-} (s) - 7 +  3y^{-}(s) = \frac{9}{s^{2} }

Taking common y⁻(s) and simplification, we get

             ( s +  3)y^{-}(s) = \frac{9}{s^{2} }+7

             y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}

<em>Step(iii</em>):-

<em>By using partial fractions , we get</em>

\frac{9}{s^{2} (s+3} = \frac{A}{s} + \frac{B}{s^{2} } + \frac{C}{s+3}

  \frac{9}{s^{2} (s+3} =  \frac{As(s+3)+B(s+3)+Cs^{2} }{s^{2} (s+3)}

 On simplification we get

  9 = A s(s+3) +B(s+3) +C(s²) ...(i)

 Put s =0 in equation(i)

   9 = B(0+3)

 <em>  B = 9/3 = 3</em>

  Put s = -3 in equation(i)

  9 = C(-3)²

  <em>C = 1</em>

 Given Equation  9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Comparing 'S²' coefficient on both sides, we get

  9 = A s²+3 A s +B(s)+3 B +C(s²)

 <em> 0 = A + C</em>

<em>put C=1 , becomes A = -1</em>

\frac{9}{s^{2} (s+3} = \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}

<u><em>Step(iv):-</em></u>

y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}

y^{-}(s)  =9( \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}) + \frac{7}{s+3}

Applying inverse Laplace transform on both sides

L^{-1} (y^{-}(s) ) =L^{-1} (9( \frac{-1}{s}) + L^{-1} (\frac{3}{s^{2} }) + L^{-1} (\frac{1}{s+3}) )+ L^{-1} (\frac{7}{s+3})

<em>By using inverse Laplace transform</em>

<em></em>L^{-1} (\frac{1}{s} ) =1<em></em>

L^{-1} (\frac{1}{s^{2} } ) = \frac{t}{1!}

L^{-1} (\frac{1}{s+a} ) =e^{-at}

<u><em>Final answer</em></u>:-

<em>Now the solution , we get</em>

Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3t}

           

           

5 0
3 years ago
Solve (x + 2 &lt; 5) ∩ (x - 7 &gt; -6).
garri49 [273]

Let A=x+2\lt5, B=x-7\gt6.

Simplifying both you get A=x\lt3,B=x\gt1.

The set conjunction is A\cap B=1\lt x\lt3.

So the answer is B.

Hope this helps.

3 0
2 years ago
Read 2 more answers
Which of the following is equivalent to xy3z2 + y2z + xyz when it is completely factored?
juin [17]
<span>xy</span>³<span>z</span>²<span> + y</span>²<span>z + xyz =
yz(xy</span>²z + y + x<span>)

Answer: C.</span>
3 0
3 years ago
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