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Leni [432]
3 years ago
6

How to solve this problem

Mathematics
2 answers:
Klio2033 [76]3 years ago
4 0

Answer:

there is no picture or anything

insens350 [35]3 years ago
3 0
What’s da problem that u have?
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Are 2/7 and 6/21 equivalent ratios
ra1l [238]
6 / 2 = 3
21 / 7 = 3

Yes, 2/7 and 6/21 are equivalent ratios.  The second number is simply the first number tripled.  
5 0
3 years ago
Read 2 more answers
HELP!!!! I’LL GIVE THE BRIANLIEST TO WHOEVER GETS IT RIGHT!!!!
Leto [7]

Answer:

13 units

Step-by-step explanation:

D is at (1,6) and C is at (-4,-6)

The distance is found by

d = sqrt(( y2-y1)^2+ (x2-x1)^2))

  = sqrt( ( -6-6)^2 + (-4-1)^2)

  = sqrt(  -12^2 + -5^2)

  = sqrt( 144+ 25)

   = sqrt( 169)

   = 13

6 0
3 years ago
What does AE equal to ?
sasho [114]

Answer:

i think its 70

Step-by-step explanation:

35+35=70

because line ## is same as ## and ##

3 0
3 years ago
I don't understand this question can you help me please
Maslowich
I believe the answer is A because the formula for area is length times width. 
5 0
3 years ago
Read 2 more answers
A triangle has a base of 3⅖ inches and an area of 5⅒ square inches. Find the height of the triangle. Show your reasoning
N76 [4]

Answer: 3 in.

Step-by-step explanation:

Given

The base of the triangle is 3\frac{2}{5}\ inches

The area of the triangle is 5\frac{1}{10}\ inches^2

Solve mixed fraction

Base is

=3\dfrac{2}{5}\\\\=\dfrac{17}{5}\ in.

Area is

=5\dfrac{1}{10}\\\\=\dfrac{51}{10}\ in.^2

The area of the triangle is given by

\Rightarrow \text{Area A=}\dfrac{1}{2}\times \text{base}\times \text{height}

Insert the values to get the height

\Rightarrow \dfrac{51}{10}=\dfrac{1}{2}\times \dfrac{17}{5}\times \text{height}\\\\\Rightarrow \text{height}=3\ in.

8 0
3 years ago
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