Answer:
Since the Line is Perpendicular
m.m'=-1
The line
y=x+8
Comparing with
Y=mx + C
m=1
m.m'=-1
m'=-1/m = -1/1 = -1.
y-y' = m'(x-x')
The point it passes is (-7,8)
y-8= -1(x--7)
y-8=-1(x+7)
y-8 = -x - 7
y + x -1 = 0.
or In Slope intercept Form
Just Make y the subject
y= -x + 1 ..... This is your answer.
Hope this helps!!!
Answer:
the answer will be 18 ohkay but they will eill have more dimes than quarters
The equation for a hyperbola is (x-h)/a - (y-k)/b = 1
Or (y-k)/a - (x-h)/b = 1
h represents the x value of the coordinate
k value represents the y value of the coordinate
together they represent a point, which is the center
So (h,k) is (x,y)
The asymptote is y-k = +/- b/a (x-h)
The transverse is the line that goes through the hyperbola.
Answer:
your answer is C) A negative radius does not make sense.
Step-by-step explanation:
hope it helps ^_^
Answer:
hey preston im watching ur 7thgrade butt
Step-by-step explanation:
