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Firlakuza [10]
3 years ago
7

The difference of two numbers is 4 and their sum is -7. What is their product?

Mathematics
1 answer:
Elina [12.6K]3 years ago
3 0

Answer:

The product is 8.25

Step-by-step explanation:

Let

x-----> one number

y ----> the other number

I assume x>y

x-y=4 ----> equation A

x+y=-7 ---> equation B

Solve the system by elimination

Adds equation A and equation B

x-y=4

x+y=-7

-----------

2x=-3

x=-1.5

Find the value of y

x-y=4

-1.5-y=4

y=-1.5-4=-5.5

The numbers are -1.5 and -5.5

Find their product

(-1.5)(-5.5)=8.25

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There were n votes cast in an election. Ms. Gordy received 32% of the votes. Which expression represents the number of votes Ms.
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Answer:

Step-by-step explanation:

4 0
2 years ago
Write an inequality for x that would give this isosceles triangle and perimeter of at least 137 ft. 4x+3 2x+7
neonofarm [45]

Answer:

The inequality is 8x+17\geq 137

Step-by-step explanation:

Given : The isosceles triangle with base and side 4x+3, 2x+7.

And the perimeter is at least 137ft.

To write : An inequality for x

Solution : Let the base b=4x+3 and sides s=2x+7

The perimeter of Isosceles triangle is P=2s+b

where s=side and b=base

Now, we have given that perimeter is at least 137 ft.

Therefore, the inequality form is

2(2x+7)+(4x+3)\geq 137

4x+14+4x+3\geq 137

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5 0
3 years ago
A small business owner estimates his mean daily profit as $970 with a standard deviation of $129. His shop is open 102 days a ye
Katena32 [7]

Answer:

The probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we select appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sum of values of <em>X</em>, i.e ∑<em>X</em>, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{x}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

 \sigma_{x}=\sqrt{n}\sigma

The information provided is:

<em>μ</em> = $970

<em>σ</em> = $129

<em>n</em> = 102

Since the sample size is quite large, i.e. <em>n</em> = 102 > 30, the Central Limit Theorem can be used to approximate the distribution of the shopkeeper's annual profit.

Then,

\sum X\sim N(\mu_{x}=98940,\ \sigma_{x}=1302.84)

Compute the probability that the shopkeeper's annual profit will not exceed $100,000 as follows:

P (\sum X \leq  100,000) =P(\frac{\sum X-\mu_{x}}{\sigma_{x}}

                              =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

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What is the value of 35 To the second power
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