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Firlakuza [10]
3 years ago
7

The difference of two numbers is 4 and their sum is -7. What is their product?

Mathematics
1 answer:
Elina [12.6K]3 years ago
3 0

Answer:

The product is 8.25

Step-by-step explanation:

Let

x-----> one number

y ----> the other number

I assume x>y

x-y=4 ----> equation A

x+y=-7 ---> equation B

Solve the system by elimination

Adds equation A and equation B

x-y=4

x+y=-7

-----------

2x=-3

x=-1.5

Find the value of y

x-y=4

-1.5-y=4

y=-1.5-4=-5.5

The numbers are -1.5 and -5.5

Find their product

(-1.5)(-5.5)=8.25

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0.8) 498 what is the answer​
Lina20 [59]

Step 1: We make the assumption that 498 is 100% since it is our output value.

Step 2: We next represent the value we seek with $x$x​.

Step 3: From step 1, it follows that $100\%=498$100%=498​.

Step 4: In the same vein, $x\%=4$x%=4​.

Step 5: This gives us a pair of simple equations:

$100\%=498(1)$100%=498(1)​.

$x\%=4(2)$x%=4(2)​.

Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS

(left hand side) of both equations have the same unit (%); we have

$\frac{100\%}{x\%}=\frac{498}{4}$

100%

x%​=

498

4​​

Step 7: Taking the inverse (or reciprocal) of both sides yields

$\frac{x\%}{100\%}=\frac{4}{498}$

x%

100%​=

4

498​​

$\Rightarrow x=0.8\%$⇒x=0.8%​

Therefore, $4$4​ is $0.8\%$0.8%​ of $498$498​.

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What is the slope of the line passing through the following points (-2,5) & (1,-7)?
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