Instantaneous rate of change = S'(r) = 8πr
S'(8) = 8π(8) = 64π
Therefore, the instantaneoud rate of change of the <span>surface area with respect to the radius r at r = 8</span> is 64π
Answer: 8.6:8.6
Explanation:
1:n is the form you want.
n is 8.6. change the n value so it is 1:8.6
1 is 1 times bigger than 8.6
8.6 times 1 is 8.6
so you've got 8.6:8.6
your welcome, i hope this helps
Answer:
Step-by-step explanation:
![\sqrt[3]{54c}=\sqrt[3]{3*3*3*2c} =3\sqrt[3]{2c}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B54c%7D%3D%5Csqrt%5B3%5D%7B3%2A3%2A3%2A2c%7D%20%3D3%5Csqrt%5B3%5D%7B2c%7D)
Answer:
Step-by-step explanation:
That is correct.
P=4s=4(12)=48in
A=s^2=12^2=144in^2
