Answer:
(a) ΔARS ≅ ΔAQT
Step-by-step explanation:
The theorem being used to show congruence is ASA. In one of the triangles, the angles are 1 and R, and the side between them is AR. The triangle containing those angles and that side is ΔARS.
In the other triangle, the angles are 3 and Q, and the side between them is AQ. The triangles containing those angles and that side is ΔAQT.
The desired congruence statement in Step 3 is ...
ΔARS ≅ ΔAQT
4
x
+
y
−
2
z
=
0
4
x
+
y
-
2
z
=
0
,
2
x
−
3
y
+
3
z
=
9
2
x
-
3
y
+
3
z
=
9
,
−
6
x
−
2
y
+
z
=
0
-
6
x
-
2
y
+
z
=
0
x
+
2
y
=
4
x
+
2
y
=
4
,
2
x
+
4
y
=
8
2
x
+
4
y
=
8
3
x
+
y
=
4
3
x
+
y
=
4
,
6
x
−
7
y
=
2
So P(-0.7537 < z < 1.3190) = 0.9063 - 0.2254 = 0.6809
Answer:
Step-by-step explanation:
Given the information:
- A'B'C' reflection over x = −1
- dilation by a scale factor of 4 from the origin
<=> the two triangles are similar to each other, triangles are similar if they have the same shape, but can be different sizes, so A″B″C″ is 4 time bigger than ABC
=> the relationship between ΔABC and ΔA″B″C″
=
We choose C.
Hope it will find you well.
Answer:
Step-by-step explanation:
The ratio of boys to girls is
7
:
11
, and there are
49
boys, so therefore there are
49
7
⋅
11
=
77
girls
Total number of boys and girls in the classroom is
77
+
49
=
126
.
