Answer:
The given statement is true.
Step-by-step explanation:
In order to inscribe a circle in a triangle, the circle's center must be placed at the incenter of the triangle.
This statement is true.
The INCENTER is the center of the circle that is inscribed in the triangle. Like the centroid, the incenter is always inside the triangle.
Answer:
(5−6)2+(−15+12)2=(5−2)2+(−15+14)2
Step-by-step explanation:
Circle equation is : (x -h)^2 + (y - k)^2 = r^2
center (h, k) = (5, -15)
r = Distance from (5, -15) to point A (2, -14)
r = root ( (5 - 2)^2 + (-15 - (-14))^2 )
r = root ( 3^2 + 1^2)
r = root(10)
Equation is (x - 5)^2 + (y + 15)^2 = 10
Check point P(6, -12)
(6 - 5)^2 + ( (-12) + 15 )^2 check if this equals 10
1^2 + 3^2 = 1 + 9 = 10, 10 = 10 good
It is the same as using the equation:
(5−6)2+(−15+12)2=(5−2)2+(−15+14)2
Answer: 
Step-by-step explanation:
<em>let's take the two given distances and add them together</em>
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<em>Now let's make give them a common denominator of 70</em>
<em>To do this we need to multiply </em>
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Sample size, n = 75
Point estimate, p = 52/75 = 0.693
Z at 99.7% confidence interval ≈ 2.96
Population mean interval = p+/- Z*Sqrt [p(1-p)/n]
Substituting;
Population mean interval = 0.693 +/- 2.96*Sqrt [0.693(1-0.693)/75] = 0.693+/-0.158 = (0.535,0.851) or (53.5%,85.1%)
Answer:
-2-(-16)=14
Step-by-step explanation:
Use KCC rule
