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tankabanditka [31]
10 months ago
5

Is it possible to draw a quaderilateral that is not a trapezoid and not a parallelogram

Mathematics
1 answer:
Scrat [10]10 months ago
5 0

Answer:

Yes

Step-by-step explanation:

A square is a quadlirateral.

A rectangle is a quadrilateral.

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Factor 2pq - 5qr + 10r - 4p.
Tresset [83]
The answer is B) <span>(q - 2)(2p - 5r) 

</span>2pq - 5qr + 10r - 4p = 2pq - 4p - 5qr + 10r
                                 = 2pq - 4p - (5qr - 10r)
                                 = 2p(q - 2) - 5r(q - 2)
                                 = (q - 2)(2p - 5r)
5 0
3 years ago
Find the square root. <br> -√1/9
harina [27]

Answer:

-1/9

that's the answer.

BRAINLIEST PLEASE

4 0
2 years ago
The first term of a geometric sequence is 32, and the 5th term of the sequence is 818 .
sammy [17]

Answer:

32,24,18,\frac{27}{2} ,\frac{81}{8}

Step-by-step explanation:

Let x, y , and z be the numbers.

Then the geometric sequence is 32,x,y,z,\frac{81}{8}

Recall that  term of a geometric sequence  are generally in the form:

a,ar,ar^2,ar^3,ar^4

This implies that:

a=32 and ar^4=\frac{81}{8}

Substitute a=32 and solve for r.

32r^3=\frac{81}{8}

r^4=\frac{81}{256}

Take the fourth root to get:

r=\sqrt[4]{\frac{81}{256} }

r=\frac{3}{4}

Therefore x=32*\frac{3}{4} =24

y=24*\frac{3}{4} =18

z=18*\frac{3}{4} =\frac{27}{2}

8 0
2 years ago
2x^3-3x^2-11x+6 divide by x-3
Alexxx [7]

Answer: 2x^2+3x-2

Step-by-step explanation:

You can do long division, which is very very hard to show with typing on a keyboard. You essentially want to divide the leading coefficient for each term. Ill try my best to explain it.

Do \frac{2x^3}{x}=2x^2. Write 2x^2 down. Now multiply (x - 3) by it. Then subtract it from the trinomial.

2x^2*(x-3)=2x^3 -6x^2\\(2x^3 -3x^2-11x+6)-(2x^3-6x^2) = 3x^2-11x+6

Now do \frac{3x^2}{x} =3x. Write that down next to your 2x^2. Multiply 3x by (x - 3) to get:

3x(x-3)=3x^2-9x\\(3x^2-11x+6)-(3x^2-9x)=-2x+6

Your final step is to do \frac{-2x}{x} =-2. Write this -2 next to your other two parts

Multiply -2 by (x - 3) to get:

-2(x-3)=-2x+6\\(-2x+6)-(-2x+6)=0

Our remainder is 0 so that means (x - 3) goes into that trinomial exactly:

2x^2+3x-2 times

4 0
2 years ago
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5x and 7x? are like terms<br> True<br> Or False
Serjik [45]

Answer:

True

Step-by-step explanation:

8 0
3 years ago
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