1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Fynjy0 [20]
3 years ago
15

Killian went to the movies with his mother, 2 brothers, and 2 sisters. The theater had choices of 2 different types of soda and

3 different types of candy. If each person ordered a soda and box of candy, is it possible for each person in Killian's family to order a different combination? Be sure to show your work and explain your answer for full credit!!
Mathematics
1 answer:
Assoli18 [71]3 years ago
4 0

yes it is possible for them all to have a different combination

his brother could have soda A and candy A

while the other brother had soda B and candy B

then his sister could have soda C and candy B

then his other sister could have soda C and candy A

while finally killian could have soda B and candy A

 

You might be interested in
Brian’s school locker has a three-digit combination lock that can be set using the numbers 5 to 9 (including 5 and 9), without r
andreev551 [17]
The possible digits are: 5, 6, 7, 8 and 9. Let's mark the case when the locker code begins with a prime number as A and the case when <span>the locker code is an odd number as B. We have 5 different digits in total, 2 of which are prime (5 and 7).

First propability:
</span>P_A=\frac{2}{5}=40\%
<span>
By knowing that digits don't repeat we can say that code is an odd number in case it ends with 5, 7 or 9 (three of five digits).

Second probability:
</span>P_B=\frac{3}{5}=60\%
5 0
3 years ago
Help asap!!! <br><br> exponential function matching table..?
masha68 [24]

Answer:

Step-by-step explanation:

Exponential equations have the form of a geometric sequence

y=ar^x\text{ y=final value, a=initial value, r=common ratio, x=term number}\\ \\ \text{The common ratio is found by dividing any term by the previous term, in this case}\\ \\ r=\frac{1}{3},\ a=27\\ \\ f(x)=27\left(\frac{1}{3}\right)^x

6 0
2 years ago
The time, t, required to drive to a certain distance varies inversely with the speed, r. if it takes 12 hours to drive the dista
kap26 [50]
T = k/R  where k is the constant of variation, T=time and R=speed.
Plug in the given values:-
12 = k/60
k = 12*60 = 720
So the equation of variation is T = 720/R

At 85 mph we have

T = 720 / 85 =  8.47 hours (answer)

8 0
3 years ago
4x + 20=? it’s hard and i’m confused
NikAS [45]

Answer:

4(x+5) I

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
One cell phone plan charges $20 per month plus $.15 per minute used. A second cell phone plan charges $35 per month plus $.10 pe
SOVA2 [1]

20+0.15x = 35+0.10x

0.15x=15+0.10x

0.05x=15

x= 15/0.05

x= 300minutes


check:

300*.015 = 45+20=65

300*0.10 = 30 + 35 = 65

they equal

 so number of minutes would be 300

7 0
3 years ago
Other questions:
  • If Bert had 3 cents more he would have twice as much as Georgia. If he had 4 cents less, he would have the same amount. How many
    5·2 answers
  • The pth percentile is a value such that approximately a. p percent of the observations are less than the value and (100 - p) per
    11·1 answer
  • 440 miles decreased by 95 percent
    12·2 answers
  • How do u write 3 less than the product of 4 and a number
    15·1 answer
  • I need help on this to​
    9·1 answer
  • What is the area of the manhole if it is 2 ft wide use 3.14 as pi and round to the nearest hundredth
    13·1 answer
  • (4,?) is in line y=2/7x-3. Find the other half of the coordinate
    14·1 answer
  • Solve the equation for all real values of x.<br> cosxtanx - 2 cos^2 x=-1
    10·1 answer
  • Six friends are buying pizza for dinner. Their choices are to buy 2 medium 10 inch diameter pizzas for $7, or one large 14 inch
    12·1 answer
  • Find the surface area. please help me
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!