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Fynjy0 [20]
4 years ago
15

Killian went to the movies with his mother, 2 brothers, and 2 sisters. The theater had choices of 2 different types of soda and

3 different types of candy. If each person ordered a soda and box of candy, is it possible for each person in Killian's family to order a different combination? Be sure to show your work and explain your answer for full credit!!
Mathematics
1 answer:
Assoli18 [71]4 years ago
4 0

yes it is possible for them all to have a different combination

his brother could have soda A and candy A

while the other brother had soda B and candy B

then his sister could have soda C and candy B

then his other sister could have soda C and candy A

while finally killian could have soda B and candy A

 

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CAN SOMEBODY PLEASE HELP ME???? I DONT UNDERSTAND AT ALL AND I NEED HELP PLEASE THANK YOU IF YOU CAN HELP ME!!!!!
marshall27 [118]

Answer:

9 possible combinations: RGB, RYG, RGB, OYG, OGB, OBP, YGB, YBP, GBP

Step-by-step explanation:

  • <em> We need to consider The Triangle Inequality Theorem which states that the sum of any 2 sides of a triangle must be greater than the measure of the third side. </em>

<u>Let's see what are the possible combinations: </u>

3+4= 7 so possible 3rd side is 5

  • 3, 4, 5 or ROY

3+5= 8 so possible 3 rd side is 7

  • 3, 5, 7 or RYG

3+7= 10 so possible 3rd side is 5 or 9 (5 is repeat of the one above)

  • 3, 7, 9 or RGB

3+9= 12 so possible 3rd side is 7, see one above

3+12= 15 so possible 3 rd side is none

4+5=9 so possible 3rd side is 7

  • 4, 5, 7 or OYG

4+7= 11 so possible 3rd side is 9

  • 4, 7, 9 or OGB

4+9= 13 so possible 3rd side is 12

  • 4, 9, 12 or OBP

5+7= 12 so possible 3rd side is 9

  • 5, 7, 9 or YGB

5+9= 14 so possible 3rd side is 12

  • 5, 9, 12 or YBP

7+9= 16 so possible 3rd side is 12

  • 7, 9, 12 or GBP

So the possible 9 combinations are:

RGB, RYG, RGB, OYG, OGB, OBP, YGB, YBP, GBP

3 0
3 years ago
Read 2 more answers
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