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Georgia [21]
3 years ago
11

In 56 years Kevin will be 9 times as old as he is right now. How old is he right now?

Mathematics
1 answer:
Artyom0805 [142]3 years ago
4 0
Kevin is 6-7 years old as 6.2222222222 x 9 is 56
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Anybody know the answers??? Helpppp
goldenfox [79]

Answer:

2. x = 135

Step-by-step explanation:

im not sure about question 1

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2 years ago
A square lawn has area 128128 ft squared .ft2. a sprinkler placed at the center of the lawn sprays water in a circular pattern t
fenix001 [56]
For this case what you must do is find the diagonal of the square to find the diameter of the circle and then be able to obtain the radius.
 We have then:
 A = L ^ 2 = 128
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 d = root ((L) ^ 2 + (L) ^ 2)
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3 years ago
Prove that if {x1x2.......xk}isany
Radda [10]

Answer:

See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where n\geq 2. If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

Proof

Since we have a if and only if w need to proof the statement on the two possible ways.

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We suppose the set X= (x_1, x_2,....,x_n) is linearly dependent, so then by definition we have scalars c_1,c_2,....,c_n in C such that:

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And not all the scalars c_1,c_2,....,c_n are equal to 0.

Since at least one constant is non zero we can assume for example that c_1 \neq 0, and we have this:

c_1 v_1 = -c_2 v_2 -c_3 v_3 -.... -c_n v_n

We can divide by c1 since we assume that c_1 \neq 0 and we have this:

v_1= -\frac{c_2}{c_1} v_2 -\frac{c_3}{c_1} v_3 - .....- \frac{c_n}{c_1} v_n

And as we can see the vector v_1 can be written a a linear combination of the remaining vectors v_2,v_3,...,v_n. We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select v_1 and we have this:

v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n

For scalars defined c_2,c_3,...,c_n in C. So then we have this:

v_1 -c_2 v_2 -c_3 v_3 - ....-c_n v_n =0

So then we can conclude that the set X is linearly dependent.

And that complet the proof for this case.

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ivanzaharov [21]

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