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tekilochka [14]
3 years ago
13

If you roll a die three times, what is the probability of rolling three ONES?

Mathematics
1 answer:
aniked [119]3 years ago
6 0

Answer:

0.004

Step-by-step explanation:

The probability of rolling any number is 1/6 so that times 3 is 1/216 that as a decimal i 0.004

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Crown the other person brainliest

Step-by-step explanation:

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3 years ago
Please show me how to do this ? Thank you :)
Bumek [7]

Answer:

<h2>2 c. = 1 pt.</h2><h2>2 pt. = 1/4 qt.</h2><h2>1 gal. = 4 qt.</h2><h2>4 qt = 1 gal.</h2>

Step-by-step explanation:

\boxed{1gal.=4qt.=8pt.=16c}\\\\1pt.=2c.\Rightarrow 2c.=1pt.\\\\1qt.=8pt.\to1pt.=\dfrac{1}{8}qt.\Rightarrow2pt.=2\cdot\dfrac{1}{8}qt.=\dfrac{1}{4}qt.\\\\1gal=4qt.\Rightarrow4qt.=1gal.

7 0
3 years ago
In factored form please help
Brilliant_brown [7]

Answer:

3rd option

Step-by-step explanation:

\frac{3x^2-3}{x^2-5x+4} ( factorise numerator and denominator )

3x² - 3 ← factor out 3 from each term

= 3(x² - 1²) ← x² - 1 is a difference of squares and factors in general as

a² - b² = (a - b)(a + b)

x² - 1

= x² - 1²

= (x - 1)(x + 1) , then

3x² - 3 = 3²(x - 1)(x + 1) ← in factored form

--------------------------------

x² - 5x + 4

consider the factors of the constant term (+ 4) which sum to give the coefficient of the x- term (- 5)

the factors are - 1 and - 4 , since

- 1 × - 4 = + 4 and - 1 - 4 = - 5 , then

x² - 5x + 4 = (x - 1)(x - 4)

then

\frac{3x^2-3}{x^2-5x+4} = \frac{3(x-1)(x+1)}{(x-1)(x-4)} ← in factored form

3 0
2 years ago
33 - (4)(2)<br> ????????????
Archy [21]
33 - (4)(2) = 33 - 8 = 25
8 0
3 years ago
Read 2 more answers
(x5 - 10x2 - 8) (x - 2)
krek1111 [17]

x5 - 10x2 - 8
—————————————
x - 2
3 0
3 years ago
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