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Lelechka [254]
3 years ago
13

My answer is correct ?

Mathematics
1 answer:
vredina [299]3 years ago
8 0

Answer:

Yes

Step-by-step explanation:

You might be interested in
A football is punted from a height of 2.5 feet above the ground with an initial vertical velocity of 45 feet per second.
Vikentia [17]

Answer:

1.451 seconds.  Hurry.

Step-by-step explanation:

The position(height, h) of the foot ball will be given by the equation:

h = -32.2t^2 + 45t + 2.5

The term -32.2t^2 consists of the acceleration caused by gravity at Earth's surface ( -32 ft/sec^2) and the term +45t accounts for the initial velocity.  The + is assigned since the ball is moving vertically from ground.  The negative sign in -32t^2 is due to the acceleration being towards ground.  The term 2.5 accounts for the fact that the initial height of the ball is 2.5 feet above ground.

We can either calculate or graph with this function to find the time the ball spends in the air:

<u>Calculate: </u>

h = -32.2t^2 + 45t + 2.5

We need a value of t that would cause h to be 5.5 feet, the level it was caught:

5.5 = -32.2t^2 + 45t + 2.5

-32.2t^2 + 45t + 2.5 = 5.5

-32.2t^2 + 45t -3.0  = 0

Solve for t using the quadratic formula.  I get a value of 1.33 seconds.

<u>Graph:</u>

See the attached graph.  It confirms the 1.33 second value

8 0
2 years ago
There are 7 students in a class. If there are 3 seats in the front row, how many ways can the students sit in the front row, ass
oksian1 [2.3K]

Answer:

<h2>35 different ways</h2>

Step-by-step explanation:

Since there are 7 students in a classroom to fill a front row containing 3 seats, we will apply the combination rule since we are to select 3 students from the total number of 7 students in the class.

In combination,<em> if r objects are to be selected from a pool of n objects, this can be done in nCr number of ways.</em>

<em>nCr = n!/(n-r!)r!</em>

Selecting 3 students from 7 students to fill the seats can therefore be done in 7C3 number of ways.

7C3 = 7!/(7-3)!3!

7C3 = 7!/(4)!3!

7C3 = 7*6*5*4!/4!*3*2

7C3 = 7*6*5/6

7C3 = 7*5

7C3 = 35

<em>Hence there are 35 different ways that the student can sit in the front assuming there are no empty seats.</em>

3 0
3 years ago
Help guys but thanks to your help I got a 100 on my homework yesterday .
Alexeev081 [22]
Easy peasy
1.
d=number of dudes
l=number of ladies
total is 55 so
d+l=55

total cost is 75 so
2d+l=75
multiply first eeuqaiton by -1 and add to second

2d+l=75
<u>-d-l=-55 +</u>
d+0=20

d=20
sub
d+l=55
20+l=55
l=35
35 ladies




2.
ratio and proportion
$87 is to 8 as is $x is to 5
87/8=x/5
times both sides by 5
435/8=x
use calculator
54.375=x
round
$54.38 recieved


3.
around the edge
means perimiter
disregard how deep the pool is

60 feet long
x wide
P=2(L+W)
P=220
220=2(60+x)
divide 2
110=60+x
minus 60 both sides
50=x
it has to be 50 feet wide




4. monthly over 5 years
1 year=12 months
12 times 5=60 months
12381/60=206.35 per month
$206.35

5.
total-food-gas-utilities=left
1624-256-125-150=1093 left
you should be able to do this one no problem
$1093 let





1. 35 ladies
2. $54.38
3. 50 feet
4. $206.35
5. $1093
3 0
3 years ago
Please answer it fast​
Afina-wow [57]

Answer:

0 and - 10

-4 and - 15

Step-by-step explanation:

5 + (-1) = 5 - 1 = 4

Which does lie between

  • 0 and - 10
  • -4 and - 15

Hope it helps you in your learning process

8 0
3 years ago
Read 2 more answers
1. A 20 kg object is thrown with an initial upward velocity of 2 m/s. If air resists motion of the object by 4 N for each m/s, w
dlinn [17]

Answer:

  49 m/s

Step-by-step explanation:

We don't know what your model is, so we'll solve this based on the balance of forces. Air resistance exerts an upward force of ...

  (4 N/(m/s))v

Gravity exerts a downward force of ...

  (20 kg)(9.8 m/s²) = 196 N

These are balanced (no net acceleration) when ...

  (4 N/(m/s))v = 196 N

  v = (196 N)/(4 N/(m/s)) = 49 m/s

The terminal velocity is expected to be 49 m/s.

4 0
3 years ago
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