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Anastasy [175]
4 years ago
14

Solve the equation 7x25=30

Mathematics
1 answer:
oksian1 [2.3K]4 years ago
4 0

Answer:

x = -(-30/7)^(1/25) or x = (30/7)^(1/25) or x = (-1)^(2/25) (30/7)^(1/25) or x = -(-1)^(3/25) (30/7)^(1/25) or x = (-1)^(4/25) (30/7)^(1/25) or x = -(-1)^(1/5) (30/7)^(1/25) or x = (-1)^(6/25) (30/7)^(1/25) or x = -(-1)^(7/25) (30/7)^(1/25) or x = (-1)^(8/25) (30/7)^(1/25) or x = -(-1)^(9/25) (30/7)^(1/25) or x = (-1)^(2/5) (30/7)^(1/25) or x = -(-1)^(11/25) (30/7)^(1/25) or x = (-1)^(12/25) (30/7)^(1/25) or x = -(-1)^(13/25) (30/7)^(1/25) or x = (-1)^(14/25) (30/7)^(1/25) or x = -(-1)^(3/5) (30/7)^(1/25) or x = (-1)^(16/25) (30/7)^(1/25) or x = -(-1)^(17/25) (30/7)^(1/25) or x = (-1)^(18/25) (30/7)^(1/25) or x = -(-1)^(19/25) (30/7)^(1/25) or x = (-1)^(4/5) (30/7)^(1/25) or x = -(-1)^(21/25) (30/7)^(1/25) or x = (-1)^(22/25) (30/7)^(1/25) or x = -(-1)^(23/25) (30/7)^(1/25) or x = (-1)^(24/25) (30/7)^(1/25)

Step-by-step explanation:

Solve for x:

7 x^25 = 30

Hint: | Divide by an appropriate factor to make the coefficient of x^25 equal to 1.

Divide both sides by 7:

x^25 = 30/7

Hint: | Take 25^th roots of both sides.

Taking 25^th roots gives (30/7)^(1/25) times the 25^th roots of unity:

Answer: x = -(-30/7)^(1/25) or x = (30/7)^(1/25) or x = (-1)^(2/25) (30/7)^(1/25) or x = -(-1)^(3/25) (30/7)^(1/25) or x = (-1)^(4/25) (30/7)^(1/25) or x = -(-1)^(1/5) (30/7)^(1/25) or x = (-1)^(6/25) (30/7)^(1/25) or x = -(-1)^(7/25) (30/7)^(1/25) or x = (-1)^(8/25) (30/7)^(1/25) or x = -(-1)^(9/25) (30/7)^(1/25) or x = (-1)^(2/5) (30/7)^(1/25) or x = -(-1)^(11/25) (30/7)^(1/25) or x = (-1)^(12/25) (30/7)^(1/25) or x = -(-1)^(13/25) (30/7)^(1/25) or x = (-1)^(14/25) (30/7)^(1/25) or x = -(-1)^(3/5) (30/7)^(1/25) or x = (-1)^(16/25) (30/7)^(1/25) or x = -(-1)^(17/25) (30/7)^(1/25) or x = (-1)^(18/25) (30/7)^(1/25) or x = -(-1)^(19/25) (30/7)^(1/25) or x = (-1)^(4/5) (30/7)^(1/25) or x = -(-1)^(21/25) (30/7)^(1/25) or x = (-1)^(22/25) (30/7)^(1/25) or x = -(-1)^(23/25) (30/7)^(1/25) or x = (-1)^(24/25) (30/7)^(1/25)

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You've answered a and b part of the question, already.

See extracts below

------------------- Answered to Question a and b begins here

"a. What assumptions must be made in order to use the binomial probability distribution to calculate the probability that a particular kind of golf ball will be removed?

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C. The experiment consists of n identical trials. The number of outcomes can vary. The probability of success can change. The trials are independent.

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--------------------------- Answer to Question a and b stops here

I'll continue from c and then proceed to d..

c.

Mean is calculated by np

where n = number of observation i.e. sample size = 5 dozens = 5 * 12 = 60

p = probability of success = 20% = 0.2

Mean, E(x) = 0.2 * 60 = 12

Standard Deviation is calculated by the SquareRoot of the products of mean by q (

Standard Deviation = √npq

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q = 1 - 0.2

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d.

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x represents the number of balls that didn't meet USGA minimum diameter

And y represents the number of balls that meet USGA minimum diameter

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i.e. p of y = 1 - 0.2

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q = 1 - 0.8 = 0.2

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Standard Deviation = 3.098386676965933

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